Parts number transistors

The problem is that the driver circuit is also damaged. Try powering up the unit with the output transistors disconnected. Measure each pad and report the results here. You should see something like 0.6,B+,0.0 on each set of three. Some will be negative rather than + (-0.6,B-, 0.0).

Keep us posted.
Dan

If it's blowing the fuse, then there are probably shorted output transistors in the amp that need to be replaced.

Problem is most likely shorted output transistors. These are the large transistors mounted on the heatsink. When these go short, they usually take out some the adjoining resistors in that channel.

Oki Data Americas, Inc., today introduced the ultra-compact OKIPAGE 8z Digital LED printer, a high-performance, practical alternative to inkjets for personal, business-class printing. The OKIPAGE 8z is the ideal printer for any desktop -- in your corporate office, your home office, Classroom or dorm.

With a suggested retail price of $249.00 and sharp 600 dpi-class output, the OKIPAGE 8z is an 8 page-per-minute (PPM) digital LED monochrome page printer designed for business professionals.

I’m happy to help further over the phone at https://www.6ya.com/expert/jeremy_69f3cc28d95bf514

use VLC palyer and can be free download from download.com

I am afraid you cannot use the TI8xPlus family of calculators to solve linear systems in matrix form. In this calculator, matrices must have real coefficients.
You can however separate (expand) the problem into a linear system of 4 equations in 4 unknowns and try to solve it with the calculator.

1. define X = a+i*b
2. Define Y=c+i*d
3. Rewrite the first equation substituting a+i*b for X and c+i*d for y.
4. Gather all real terms together, and all imaginary terms together on the left.
5. You will have (8a-15b-8c) +i(15a+8b-8d) = 10 +0i
6. This equation can be split into two equations by saying that

• the real part pf the left member is equal to the real part of the right member, this gives 8a-15b-8c=10, and
• the imaginary part of the left member is equal to the imaginary part of the right member, this gives 15a+8b-8d=0

Similarly, you rewrite the second complex equation substituting a+ib for X and c+id for Y, then expand the binomial products, gather the real parts on the left together, and the imaginary parts on the left together. After that you equate the real part on the left to the real part on the right, and do the same for the imaginary parts.

If I did not make mistakes during the expansions and the gathering of terms you should get the following equation
-(8a+8c+10d) +i*(-8b+10c-8d) =0+i*0 from which you extract an equation for the real parts, -(8a+8c+10d)=0 and another for the imaginagy parts i*(-8b+10c-8d) =i*0

If I did not make mistakes (you should be able to find them, if any) your system of two linear equations with complex coefficents has been converted to a system of 4 linear equations with real coefficients.

8a-15b-8c=10
15a+8b-8d=0
8a+8c+10d=0
-8b+10c-8d =0

Now, you can in theory solve this system with help of the calculator, to find a, b, c, and d. When these are found, you can reconstruct the X and Y solutions.

Now get to work: Ascertain that my extracted equations are correct, then solve for a, b,c, and d, and reconstruct X and Y.
I am no seer, but my hunch is that this system is degenarate. I will not explain what that means.

Porblem solved,
It's a wonderful day.... Ahhhh, it is now FIXED and working great. I found cracked solder joints on a few of the switching power transistors and some of the big diodes and other heat producing parts. Also notice that the infamous Red caps C524 and C523 were discolored but they checked OK on my cap meter and also my ohm meter, however while I was inside the set after removing 1 million scews I decided to replace them anyway.
I hope that my repair success helps someone.
electricitym

1-800-295-1980 8a.m.-5p.m.

the part number for the sony OEM remote is 1-476-680-12. you can get it at www.vancebaldwin.com for $18.95 they have 12 of them.