Find each value? 2! 0! - Texas Instruments TI-83 Plus Calculator

Let's do the preocess so it will work on any calculator.

As an example, convert 68 from decimal to binary.

The decimal columns are 10^0, 10^1, 10^2, 10^3, etc.

The binary columns are 2^0, 2^1, 2^2, 2^3, etc.

Flipping to the normal left to right, we get 2^6, 2^5, 2^4, 2^3, 2^2, 2^1, 2^0.

64 32 16 8 4 2 1

We divide our number, 68, by 64, and get 1 with a remainder of 4. We next divide our remainder by 32, 16, 8, and finally 4, where we get 1 with no reminder.

In binary, this works out to 1000100. To check, we multiply the ones by the respective column values and get 64 + 4 = 68.

Good luck.

Paul

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The question is incomplete.
The mean, also called the average is defined as
mean= (sum of the data values)/(number of data elements)
Mode = the most frequent data value (the one that is most repeated)
To find the median:

1. Order the data values in ascending order (sort them from the smallestr to the largest), and
2. Locate the data value that is in the middle.
3. If the number of data values id ODD (not a multiple of 2) there is only one middle element. That is the median.
4. If the number of data elements is EVEN (multiple of 2), there is not one middle element but two.
5. The median is the average of the two middle element values


1. Median =( left of middle value +right of middle value)/2
2. Imagine this median value to be inserted between the two middle elements

Example 1
Data values 12.5, 13, 13., 13, 13.5, 14, 19.5, 19.5, 20
Mean =(12.5+13+13+13+13.5 +14+19.5+19.5+20)/9=?
Mode= most frequent value. Here it is 13 (repeated 3 times)
There are 9 values, an odd number. Middle element is the 5th ( 13.5)
Median=13.5

Example 2
Data values 12.5, 13, 13., 13, 13.5, 14, 19.5, 19.5, 20, 25
Mean =(12.5+13+13+13+13.5 +14+19.5+19.5+20 + 25)/10=?
Mode= most frequent value. Here it is 13 (repeated 3 times)
There are 10 values, an even number. Middle element is not among the values. There are two middle elements (the 5th and the 6th) or
The value of the median is the average of the 5th and 6th elements or
Value of Median =(13.5+14)/2=?

When you buy it is worth $60, 000
I will assume that at the end of a year it is the whole new value of the house that is increased by 5%.
After 1 year value=60,000*(1+0.05)^1
After 2 years value=$60,000(1+0.05)*(1+0.05)=60,000*(1.05)^2
Do you see the pattern?
After 7 years, the value of the house will be 60,000*(1.05)^7

However if the increase is not compounded
Then after 1 year value=60,000*(1+0.05)
After 2 years, value=60,000*(1+0.05+0.05)=60,000*(1+2*0.05)
After 7 years, value=60,000*(1+7*0.05)

Depending on the coumpounding or not the two values will be different
With compounding: final value=$84,426.02
Without compunding: final value is $81, 000.

I showed you the possible mathematical solutions. It is now up to you to decide which is the one that applies to your case.

Hi rayalak857,

Have a nice day.


Calculator does not have a solve program, but you can use it to solve the quadratic equation with a little effort. If you know the theory skip toward the end.
Here is the example:

Let aX^2+bX+C=0
1. First calculate the discriminant usually called Delta and given by
Delta =b^2 -4*a*c store the value in the variable D
If Delta is positive you have two roots X1 and X2 given by
X1=(-b+square root of Delta)/(2*a)
X2=(-b- square root of Delta)/(2*a)

If Delta is equal to 0, X1=X2=-b/(2*a)
If Delta i negative, no real solutions exist

You only solve if Delta is positive or equal to 0.

Putting in the values of a, b, and c
value of a (put you number) [SHIFT][STO] A
value of b (put your value) [SHIFT][STO] B
value of c (put you value) [SHIF][STO] C

[ALPHA] B [X^2] -4[x][ALPHA] A [x][ALPHA] C [=]
Value of delta is displayed. If it is positive, you store its square root in D

[Square root] [ANS] [SHIFT][STO] D ;

Calculate 1/(2*a) and store in variable F
1./(2[x] ALPHA A) [SHIFT][STO] F

To obtain X1
[ALPHA] F [x] ( (-) ALPHA B + ALPHA D ) [=]
To obtain X2
[ALPHA] F [x] ( (-) ALPHA B - ALPHA D ) [=]

Be careful: the (-) is the change sign not the regular minus sign.

Hope it helps. Goodluck

Thank you for using fixya.

i am giving the key input with an example..
example-
at 0, value is 300
at 50, value is 270
so how much at 30...

On 991MS,
Go in Reg mode, for doing that : press Menu,Menu, 2

Enter the values as follows,

0,300 and press M+ key on the calci
(Note: there is a "," in between 0 and 300)

then enter the following,
50,270 and press M+ key

now enter the following input exactly as displayed below:

(30) shift 2 > > > 2 =


you will get the answer as 282.

I hope you got it!!!

LOFT!!!

Hi Geetad11

This is Horizontal lookup , used to look up value in a 2 dimensional table .It searches for a value in the top row of a table or an array of values, and then returns a value in the same column from a row you specify in the table or array. Use HLOOKUP when your comparison values are located in a row across the top of a table of data, and you want to look down a specified number of rows. The H in HLOOKUP stands for "Horizontal."

Formulae Syntax

HLOOKUP(lookup_value,table_array,row_index_num,range_lookup)

Lookup_value is the value to be found in the first row of the table. Lookup_value can be a value, a reference, or a text string.

Table_array is a table of information in which data is looked up. Use a reference to a range or a range name.

• The values in the first row of table_array can be text, numbers, or logical values.
  

• If range_lookup is TRUE, the values in the first row of table_array must be placed in ascending order: ...-2, -1, 0, 1, 2,... , A-Z, FALSE, TRUE; otherwise, HLOOKUP may not give the correct value. If range_lookup is FALSE, table_array does not need to be sorted.
  

• Uppercase and lowercase text are equivalent.
  

• You can put values in ascending order, left to right, by selecting the values and then clicking Sort on the Data menu. Click Options, click Sort left to right, and then click OK. Under Sort by, click the row in the list, and then click Ascending.
  

Row_index_num is the row number in table_array from which the matching value will be returned. A row_index_num of 1 returns the first row value in table_array, a row_index_num of 2 returns the second row value in table_array, and so on. If row_index_num is less than 1, HLOOKUP returns the #VALUE! error value; if row_index_num is greater than the number of rows on table_array, HLOOKUP returns the #REF! error value.

Range_lookup is a logical value that specifies whether you want HLOOKUP to find an exact match or an approximate match. If TRUE or omitted, an approximate match is returned. In other words, if an exact match is not found, the next largest value that is less than lookup_value is returned. If FALSE, HLOOKUP will find an exact match. If one is not found, the error value #N/A is returned.

Remarks

• If HLOOKUP can't find lookup_value, and range_lookup is TRUE, it uses the largest value that is less than lookup_value.
• If lookup_value is smaller than the smallest value in the first row of table_array, HLOOKUP returns the #N/A error value.

Example
The example may be easier to understand if you copy it to a blank worksheet.

Hello,
The calculator does not have a solve program, but you can still use it to solve the quadratic equation with a little effort. If you know the therory skip toward the end.

Let aX^2+bX+C=0
1. First calculate the discriminant usually called Delta and given by
Delta =b^2 -4*a*c store the value in the variable D
If Delta is positive you have two roots X1 and X2 given by
X1=(-b+square root of Delta)/(2*a)
X2=(-b- square root of Delta)/(2*a)

If Delta is equal to 0, X1=X2=-b/(2*a)
If Delta i negative, no real solutions exist

You only solve if Delta is positive or equal to 0.

Putting in the values of a, b, and c
value of a (put you number) [SHIFT][STO] A
value of b (put your value) [SHIFT][STO] B
value of c (put you value) [SHIF][STO] C

[ALPHA] B [X^2] -4[x][ALPHA] A [x][ALPHA] C [=]
Value of delta is displayed. If it is positive, you store its square root in D

[Square root] [ANS] [SHIFT][STO] D ;

Calculate 1/(2*a) and store in variable F
1./(2[x] ALPHA A) [SHIFT][STO] F

To obtain X1
[ALPHA] F [x] ( (-) ALPHA B + ALPHA D ) [=]
To obtain X2
[ALPHA] F [x] ( (-) ALPHA B - ALPHA D ) [=]

Be careful: the (-) is the change sign not the regular minus sign.

Hope it helps.

STO 1 puts the displayed value into memory location 1.

RCL 1 brings the stored value back.

Same for memory locations 2 and 3.

If there's something in memory, M1, M2 M3 will show in the display, clear the memory by storing the value zero.

Note that anything stored into memory location 1, 2 or 3 over writes what was there. Memory values are retained through power off/on.

To add the displayed number to a memory location (instead of replacing the value stored), use 2nd, STO, n

To exchange displayed and stored values, use 2nd, EXC, n

n is 1, 2 or 3

Get the instruction booklet from TI's website (pdf download) if you don't have one