Xpressions Media High Achiever Algebra 1 Academic License (03610) "2" Questions

How to converting 39.37 base 10 base 2? The easiest to understand (and the longest) method is to subtract off the powers of 2. The highest power of 2 in 39.37 is 2^5=32, 39.37-32 = 7.37. The next ...

The most simplified form of 3*2*2*2*4*4 is? 3*2*2*2*4*4 3*2*2*2*2*2*2*2 3*2^7 (three times 7th power of 2)

...is 800 let nos be x-d, x, x+d then (x-d)+(x)+(x+d)=48 => 3x+d -d =48 3x=48 x=48/3 x=16 now (x-d)^2 + x^2 + (x+d)^2 = 800 x^2 + d^2 -2xd + x^2 +x^2 + d^2 + 2xd=800 3x^2 + 2d^2 =800 3*(16)^2 + 2d^2 ...

Solve it plz...... cos x + root 3 sin x =root 2 cos x + root 3 sin x =root 2 cos x + ?3 * Sin x = ?2 squaring both the side (cos x + ?3 * Sin x)2 = (?2)2 Cos2 x + 3 * Sin2 x = 2 Cos2 x + Sin2 x + 2 * ...

algebra 1 C=w+t/V;t B. 2((2-Y)/3)-Y=3 2(2-Y)-Y=9 4-2Y-Y=9 -3Y=9-4 -3Y=5 -Y=5/3 Y=-1.67 A. 3X+(-1.67)=2 3X-1.67=2 3X=2+1.67 3X=3.67 X=3.67/3 X=1.22 (3x-2y)2 = 2x=4 3x+y=2;2x-y sol'n: 3x+y=2 y=2x-3 ...

Cos2x + 3 = 5cosx help Use the identity cos(2x)=2(cos(x))^2-1 cos(2x)+3=5cos(x) becomes 2(cos(x))^2-1+3=5cos(x) Arrange a bit: 2(cos(x))^2-5cos(x)+2=0 Get rid of the 2-factor (cos(x))^2-(5/2) cos(x)+1

khan academy 1/1-x -1/x =1/2 why does the common denominator become (x-1) x 2 1/1-x -1/x =1/2 why does the common denominator become (x-1) x 2 I assume this is (1 / (1-x)) - (1 / x) ....now first, ...

what is the solution for: 4 square root of 28 - 2 square root of 2/3= 20.2232014 Easy. Give me something harder next time :) Depends where you put the brackets ! 4 square root of 28 - 2 square root of

110011 TO BASE 10 Assuming the original number is base 2, the place values are: 5 4 3 2 1 0 (these are intended to be superscripts) 2 2 2 2 2 2 or: 32 16 8 4 2 1 in the question, the number was 110011

determining the equation of the parabola find the equation of the parabola with the vertex of (2,0) and focus of (2,2) V (2,0) and Focus (2,2) since the focus is 2 units above the vertex, the parabola