Find the sum of all integer multiples of 8 between 33 and 3051.

Let x be the smallest number.
Let x + 2 be the other number (consecutive even integer)

Now to translate the rest;)
three times the smaller 3(x)
19 more -19
sum of the two integers - (x) +( x+2)

Pulling it together,
3x -19 = x + x +2
collect like terms
3x - 19 = 2x + 2
Put all the constants on one side by adding 19 to both sides.
3x - 19 +19= 2x + 2 + 19
3x = 2x +21
Subtract 2x from both sides to have all the x's on one side.
3x - 2x = 2x +21 - 2x
x = 21
The other number is 21 + 2, or 23
Check:three times the smaller = 3 x 21 = 63
sum of the two integers = 21 + 23 or 44
is 63 at least 19 more than 44

129

If this is homework, be sure to show your work.

15 and 11.

If this is homework, be sure to show your work.

Here's a simple (and inefficient) 35s program. It simply goes through a loop 25 times, adding up the numbers.

A001 LBL A
A002 25
A003 STO A
A004 0
A005 RCL+ A
A006 DSE A
A007 GTO A005

The sum of the first N positive integers can be calculated more efficiently as N(N+1)/2 .

spell correctly and I will tell you :-)

#include <iostream>
using namespace std;
int main ()
{
int num = 0, i = 1, sum = 0;
cout << "Enter a positive integer: ";
cin >> num;
while (i <= num)
{
sum += i;
i++;
}
cout << "The sum is " << sum << endl;
return 0;
}

Let X be the lowest of the 3 integers
The sum of the 3 integers can be represented as X + (X+1) + (X+2).
Set this sum equal to 378 and solve for X.
X + (X+1) + (X+2) = 378
3X + 3 = 378
3X = 375
X = 125
Since X is the lowest of the 3 integers the other 2 will be X+1 and X+2 or 126 and 127.

Therefore, the answer is 125, 126 and 127

Q.2#  Dim n, sum as Double
Dim i as Integer
n=100
sum=0

for i=1 to n
sum=sum+1/n
next i

Q.3#  Dim sum as Double
sum=0
for i=1 to 99
if i%2 <> 0 then sum=sum+i end if
next i

i'll just reply to your conditional sumif query.

yes, you can do multiple criteria query but with a matrix formula. you may look it up. nonetheless, here is how one would look like:

{=sum(if(range1=A x range2=B x range3=C, sum range))} note that x (multiplication) is used to denote intersection of the criteria

initially, you'll enter it as:
=sum(if(range1=A x range2=B x range3=C, sum range))

then, edit the cell (F2) and press ctrl+shift+enter for the brackets { } to appear.