2x^2-19x+22 I'm assumeing the problem is 2x^2 - 19x+22 = 0, solve for x. I don't see any easy to factor this so I'll either need to complete the square or use the quadratic equation. Using the ...
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...+ 88X + 340 = 640 Subtract 640 from both sides: 4X^2 + 88X - 300 = 0 Divide both sides by 4: X^2 + 22X - 75 = 0 Use the quadratic equation to solve for X, with A=1, B=22, C=75 X = [-22 +/-
6m+3(2m+5)+7 6m+6m+15+7=0 12m=-22 M= -22/12
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