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Posted on Jul 10, 2011
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How to solve? john has a total of 480 chicken and cows on a farm. They have 1260 legs altogether. how many chickens than cows there are?

1 Answer

kakima

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  • Office Equip... Master 102,366 Answers
  • Posted on Jul 10, 2011
kakima
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There are 330 chickens and 150 cows, so there are 180 more chickens than cows. Since this sounds like a homework problem, you'll have to show your work.

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Julius wet dog roll 3 kg available beef and chicken but have been to 4 stores last few weeks and there is no beef available but heaps of chicken. Why

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FarmVille is a popular social networking game. When you begin playing, you must build your resources by caring for crops, trees and animals.

Once you've gotten into the game, your focus can shift. If your game seems to be going slowly, it's almost certainly not your computer. It might be because you've got too much on hand.

Reduce your livestock. The heart of the problem lies with your FarmVille animals and the fact that they are script programs that run through java script. Java script enables your Farmville animals to be animated, but when you have a lot of animals, the java script application bogs down your browser. There are two basic ways to cut your livestock to speed up your game. Go to the Market and choose the "Building" tab. There you will see the various buildings that you can purchase, either with FarmVille dollars or coins. Purchase a chicken coop and store up to 20 of your chickens, then sell the rest of your chickens. Purchase as many Dairy Farms as needed to store your cows. Because you can obtain unlimited Dairy Farms, you will not have to sell any cows. Sell all of the rest of your animals. This will eliminate the scripting issues and you will be able to plant, plow and harvest with great speed. Sell all of your animals. This might seem counter-productive, but remember that gaining higher levels in FarmVille is mainly done through harvesting crops, so your focus should be on planting and harvesting crops. You always can get animals from your FarmVille neighbors. Hope this helps.
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How to solve this problem in a different way,A FARM BOY TENDS PIGS AND CHICKENS IN THEIR YARD,hE COUNTED 21 HEADS AND 54 FEET. hOW MANY PIGS AND CHICkENs ARE THERE?pls.share me a strategy without using...

P = number of pigs

Then P is the number of pig-heads, and 4*P is the number of pigs-feet.

C = number of chickens

Then C is the number of chicken-heads, and 2*C is the number of chicken-feet.

Thus: 21 = P + C

Equivalently: 42 = 2*P + 2*C

Also: 54 = 4*P + 2*C

Thus (54-42) = 4*P + 2*C - 2*P - 2*C

Factoring: 12 = 2*P + ( 2*C - 2*C)

Reducing: 6 = P
------------------------------------------------

Or, do it on graph-paper, with 'P' on the X-axis and 'C' on the Y-axis,
and each unit representing one animal (pig or chicken).

Draw one line between (0,21) and (21,0) (no pigs & 21 chickens, versus 21 pigs & 0 chickens)

Draw one line between (0,27) [no pigs and 27 pairs of chicken-feet]
and (13,1) [13 pigs have 52 feet, with 1 pair of chicken-feet]

The two lines cross at exactly one point on the graph, namely at the solution.
--------------------------------------------------------------------------
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Re: Facebook games Farmville very slow. I'll c...

the working of your computer is no where connected with the speed of the game. The problem lies with your farm animals, which are in fact script programs that run through Java script. In short, though it is Java script which enables your animals be animated and to move, it is also sad that it is Java script applications which bog down your browser, slowing down the speed of the applications on the website/page. The more Java script means very slow speed. That is why you find Farmville going slow. Though a number of searches have been made for programs to disable scripting, it has not yielded the necessary results, and somehow it does not seem to work for Farmville. So it is definitely wise to follow other options. STEP 2.
Aim of getting rid of your animals, if you really want to eliminate scripting, to prevent it from bogging down your browser. Basically, you have only two options to do that, out of which the first one offers very little help because it applies only to cows and chickens. Farmville lets you store cows and chickens in BUILDINGS: Dairy Farm and Chicken's Coop respectively. However, right now you can buy any number of Dairy Farms to store your cows, but sadly you can obtain one chicken coop that can hold 20 chickens only.
To continue, go the Market and choose the Building tab, where you see various building that you can buy, either with Farmville dollars or coins. Purchase one chicken coop, store 20 of your chickens and SELL the rest of your chickens. You can buy as many Dairy Farms as you require to store your cows. And since you can buy unlimited Dairy farms, luckily you need not SELL any cows. With regards to the other Farm animals, SELL them to avoid scripting there by avoid slowing down the game. Your game will pick up speed once you start planting,plowing and harvesting.
STEP 3.
The second option would be to SELL ALL YOUR ANIMALS. In order to do that, simply left click on the animal ad choose SELL. A second screen will appear, and here you choose YES, to sell the animal. Selling animals may not be a very good option, but you need to choose between playing faster or slowing down your game.
STEP 4
Harvesting crops fetches you higher levels in Farmville. So you need to always keep in mind that once you have reached the higher levels by plowing, planting and harvesting innumerable corps, you can always get animals for your Farmville neighbours. You may have to sacrifice your animals to get to the top, but it is definitely a worth choice, something that one gets to learn easily.
So Enjoy Your Farming! Now, if you are new to the game, you can save your resources by mainly paying attention to getting cows and chickens and storing them in their respective buildings. Also once you sell an animal, you will be able to replace it by either buying or obtaining it from one of your neighbours, but at a later stage only.
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Rabbits and chickens

Let C = # of Chickens and R = # of Rabbits
Let CL = # of Chicken Legs and RL = # of Rabbit Legs
C + R = 52 (each chicken and each rabbit have a head)
R = 52 - C
CL = 2C (each chicken has 2 legs)
RL = 4R (each rabbit has 4 legs)

CL + RL = 148
2C + 4 (52 - C) = 148
-2C + 208 = 148
C = 30

R = 52 - C = 52 - 30
= 22

There are 30 chickens and 22 rabbits.
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How can i contact farmville director

There is a help link at the facebook page, and email them about your question.
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HOW DO I ROAST A CHICKEN IN A AC925CHS

Search the internet for “roast chicken recipe for microwave”
Here is one just in case you don’t find one:
Microwave Roast Chicken
3 lbs. chicken
1 tsp. salt
4 tbsp. butter or margarine
1 tsp. paprika

Instructions
Melt butter in a custard cup in microwave. Mix paprika into melted butter. Wash chicken (reserve giblets, these are best cooked conventionally). Sprinkle inside of chicken with salt. Cover ends of legs, tail, and wings with small pieces of saran wrap or wax paper. Place trivet on inverted saucer or small casserole lid in 12 x 7 inch baking dish. Place chicken breast side down on saucers. Brush with butter. Cover with waxed paper. Cook 12 minutes. Remove wax paper or saran warp from legs, tail, and wings. Turn chicken breast side up and brush with butter. Cover with wax paper and cook 12 minutes more or until meat thermometer registers 180 degrees (temperature will increase to 195 degrees during standing).

DO NOT USE MEAT THERMOMETER IN OVEN WHEN COOKING!! Remove chicken from oven; cover with aluminum foil and let stand 15 to 20 minutes before carving. Note: For other weights of chicken, allow 8 minutes cooking time per pound.
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