Question about Peavey SP2 PA Passive Speaker

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Hi,i got the circuit diagram of the soundguard protection u have sent, but the resistor(50w 5ohms) used in your circuit. in my circuit two resistors(25w 10ohms each) are used in parallel. so in my case what will be the wattage & voltage of the bulb. The bulb in my circuit is tube shaped. Please help.

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  • Samuel Charles Spriggs Jan 21, 2011

    Two 25 watt, 5 ohm resistors in parallel are equivalent to one 50 watt, 10 ohm resistor. I don't have the circuit diagram and there's not enough info in your post to determine the wattage and voltage of the bulb, but the bulb would be the same in either circuit.

    Charlie

  • William D'Costa
    William D'Costa Jan 22, 2011

    Thanks for your kind support. it was very much helpful. regarding my Peavey sp2 speakers

    from:wills.dcosta@yahoo.in

  • Joe Patch
    Joe Patch Feb 15, 2013

    Resistors in parallel cuts the impedence in half instead of doubling. Ohms law states the equation above would be equivalent to 50 watt 2.5 ohm resistor.

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For the MOST PART the lamp is NOT the primary path for the speaker current, the POLYFUSE is and is a low resistance until it is overdriven.

The bulb is a 12 volt bulb and is nominally 2.1 amps when used on 12.8 volts.

If this is in regards to the other problem mentioning 32 watts and 12.8 volts... this bulb is NOT 32 Watts, it is 32 CP or 32 Candlepower which is NOT Watts in general. The lamp is actually around 27 Watts when run at its ratings.

It is important to realize that the lamp and the resistor are there ONLY as a "soft" path when the POLYFUSE opens due to overcurrent. When the polyfuse cools, the lamp and resistors are effectively shorted by the Polyfuse and most of the current again flows through the polyfuse..

Posted on Jan 22, 2011

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