Try yahoo.co./ds/cheats
As the camera costs $300 more than the case and the total cost is $310, you know that the camera must cost more than $300 and be less than $310
Also consider that the cost of the case must equal however much the camera costs over $300 (since the camera costs $300 more than the case)
For example, if the case costs $1 then the camera must cost $301 (but as this doesn't total $310, it's clearly not correct)
Similarly, if the case costs $9 then the camera must cost $309 (but as this doesn't total $310, this is also not correct)
Keep considering the small number of possibilities until you find one where the camera and the case total $310
Once you work out the cost of the case, you can subtract the cost of the case from $100 to arrive at your answer (which is not clearly $0 as suggested by vikis21)
If you're still stuck, you can find the answer in this popular walkthrough
http://professorlaytonwalkthrough.blogspot.com/2008/02/puzzle042.html
The answer is 0
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