Finding area of a Triangle in the Coordinate Plane

Hi David:
You've got me confused.
A triangle has 3 sides. You have provided 4 lengths and no picture.
The hypotenuse is joins the 2 sides that are the "legs" of the right angle.
The length of the hypotenuse is the square root of the sum of the squares of the sides.
Just apply the "rule" to the appropriate dimensions.
Cheers

I find the easiest way to solve these is to sketch them first (I'm a visual learner;) We get a nice right-angled triangle, with the right-angle at B. The formula for the area of a triangle is 1/2 * base* height or (base * height)/2.

We can use BC or AB as the base.

If we use BC as the base, the length is 9-4 or 5. The height is 6-2 or 4.

We can now but the base and the height in the formula to figure out the area.

Good luck.

Paul

The area of a triangle is 1/2 times base times height. A sketch of the triangle in the coordinate plane will determine how easy or hard this will be to be. From the sketch, you will see that this is a right-angled triangle with B being the right-angle. This makes it easier because we can easily determine the base and the height to use in the formula.

We can chose AB or BC to be the base, while the other will be the height. If we choose the base of AB, its length is 4, the 6 - 2. The height is 9-(-4) or 13.

We can now put the length and height into the formula to calculate the area of the triangle.

Good luck.

Paul

How many points do you want to use?

The are of a triangle is 1/2 * the base * the height.

So if the triangle is 2 for the base and 4 for the height. it would be (2*4*1/2) or 2*4=8, 8*1/2=4. So the area of the triangle would be 4 square (until of measure).

Of course this assumes you know the base and the height of the particular triangle.
This site might be a bit more helpful for calculations where some of the numbers may not be known. Good luck!

http://www.wikihow.com/Calculate-the-Area-of-a-Triangle

Assuming you are specifying Area = sqrt(243/4) = 7.79422 Then the sides of the equilateral triangle are: 4.24264
Source: http://www.calculatorsoup.com/calculators/geometry-plane/triangles-equilateral.php
Best, Hunter

the area of the rectangle is infinite because the length of the sides is undefined.

In right triangle we are making 90 degree angle triangle, we can have problem for finding hypotenuse or finding sin or cos values of the side of the triangle. For ex,Find out the hypotenuse,sin and cos value of the right triangle with base 4 cm and perpendicular 3 cm Solution:Hypotenuse = SQRT(4^2 + 3^2) =SQRT(4*4 + 3*3) =SQRT(16+9)=SQRT(25)=5 cm For right triangle, sin(x)=3/5=0.6 cos(x)=4/5 =0.8

Hi nanaeden

Use the formula depending on what is given
If one side and vertical height from that side to the opposite vertex is given, use the formula 1/2 of basexheight
If 3 sides of the triangle are given use the formula
sq root of [ s(s-a)(s-b)(s-c)] where a,b, c are the 3 sides and s is semi- perimeter.
Familiarise with formulae to solve Maths problems.
If it is helpful, please give a rating.
Have a nice day
luciana44

get a sheet of graph paper. draw a line vertical and draw another line in the center perpendicular to the vertical. the meeting point is 0,0 - the upper right quadrant is X-Y. the bottom right quadrant is Y -X, the left bottom is -Y -X and what's left is -X +Y.
take your first coordinate. count up 2 and to the right 3. make a point. second coordinate - count up 4 and over right 1, make a point. now join the two points with a straight line. measure the distance between the points.