Sokkia Cx-105 5 Reflectorless Total Station, Laser Plummet, Dual Display Logo

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Dino Estanero Posted on Aug 20, 2014
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What is the correctio factor value of sokkia CX-105/SG

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Vuk B

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  • Posted on Dec 23, 2016
Vuk B
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ESTACION TOTAL SOKKIA CX-105 DA EL ERROR E-880 QUE SIGNIFICA

there's a website reliable-store
all heavy equipment repair issues servicing, loading, wiring, engine problems everyt hing is covered here its a must try
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In Sokkia CX 101 Total Station Error E097 comes ....What is it means and how to solve that ???

CX series

www.sokkia.com.tw/download/??/CX_series_E-copy.pdf
Jan 1, 2012 - CX-105. CX-107. Compact X-ellence Station. CLASS 2 Laser Product ... Except where stated, "CX" means CX-101/102/103/105/107. • The CX ..... Ignoring this indication and making an operation error .... Make sure that moisture or dust particles do not come in contact with the inside .... detergent solution.
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E191 for total station, sokkia type, it does not observe horizontal and vertical angle & does not measuring

Sokkia total stations are repaired using Sokkia proprietary computer software. You need to return it to a Sokkia shop, no other shop will be able to corect this, not even Topcon (even though Topcon bought Sokkia).
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Error e191 sokkia 1030r

Error e191 sokkia 1030r
Sokkia 1030r displays e191 in horizontal angle window
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Manual sokkia cx105

i want to know about methed of back side
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How to factor a polynomial equation on casio fx-300es?

Hello,
The Casio FX-300ES does not handle symbolic algebra. So it cannot factor a general polynomial expression. The methods can be found in any book on Algebra.
However if you are interested in approximate factorization of quadratic and cubic polynomials, you can use the calculator to do that. It can solve aX^3 +bX^2+cX+d =0 and the quadratic equations.

If you want to factor a cubic polynomial P3(X) = aX^3+bX^2+cX+d , you write the corresponding cubic equation as aX^3+bX^2+cX=d =0 , then you divide all terms of the equation by a to obtain

X^3+(b/a)X^2+(c/a)X+(d/a)=0.

You use the calculator to solve (approximately) this equation.
Suppose you find the 3 roots X1,X2,and X3. Then the polynomial X^3+(b/a)X^2+(c/a)X+(d/a) can be cast in the factored form (X-X1)(X-X2)(X-X3) and the original polynomial P3(X) can be written as

P3(X) = a*(X-X1)(X-X2)(X-X3)

You can handle the quadratic polynomial the same way.

P2(X) =a*(X-X1)(X-X2) where X1, X2 are the two real roots

Hope it helps.
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