SOURCE: trig and distance
Debs,
this is solved by starting with the SECOND leg of the flight considered as a triangle.
Find how far DUE east the plane travels (100 km x Cos10 = 83.9 km) using 10 degrees because that is how much is left of the 90 degree quadrent after subtracting the 80 degrres course direction.
Similarly find out how far DUE north the plane travels (100 km x Cos80 = 11 km).
Now get the total flight NORTH = 300 + 11 = 311
- and total EAST = 83.9
Finally, use Pythagoras theorem.to get the total DISTANCE:
square root of ( 311 squared + 83 squared ) = 321 km
Also the DIRECTION from its Tangent of 83 /311 = 14.9 degrees
SOURCE: mrs. lok is planning a 600-mile trip. her car has
No, she will be able to make the trip with only 1 tank of gas.
Solution:
She has an 18 gallon gas tank.
1 gallon = 29 miles
The 18 gallons / tank multiplied by the 29 miles / gallon
= 522 miles / tank
She will run out of gas in 522 miles.
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