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Posted on Sep 02, 2012

Take ten cards numbered 0 to 9 each time use all ten cards arrange the cards to make a.five numberes that are multiples of 3 b.five numbers that are multiples of 7 c.five prime numbers

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Anonymous

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  • Posted on Nov 03, 2008

SOURCE: word problems

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Anonymous

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  • Posted on Oct 16, 2009

SOURCE: three pupils are each asked to select four numbers

Zero! And....Zero!

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Round 3 to ten

Rounding 3 to the nearest tens.

The process should always be the same.

Step 1 - identify the column in question.
Step 2 - go the the column immediately to the right of this column
Step 3 - if this number is 5 or more, add 1 to the column in question and make all numbers to the right 0, or if to the right of the decimal, eliminate them.
Step 4 - if this number is 4 or less, don't add 1 to the column in question and make all number to the right 0, or if to the right of the decimal, eliminate them.

To assist, I have written the number as 03.

Step 1 - Tens column is the 0.
Step 2 - Column immediately to the right is 3
Step 3 - Number is not 5 or more
Step 4 - Number is 4 or less, set the numbers to the right to 0

The answer is 0. The numbers -4, -3, -2, -1, 0, 1, 2, 3, and 4 when rounded to the nearest 10, all round to 0.

Good luck,

Paul
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How many 5 digit arrangements (combinations) are there using numbers 1 thru 10

There are 252 combinations of ten items taken five at a time.
If the order matters then there are 300,240 permutations of ten items taken five at a time.
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How many 8 letters arrangement are possible using the letters of the word DECAGON if the letters A,E and O must occupy the third, fifth and sixth positions respectively and the letters remaining may be...

xxAxEOxx where x can be any of the letters in the set {d,c,g,n}.
There are 4 choices for the first x. Once the first x letter is chosen there are 4 choices for the second x, etc. Since you have five x positions to fill , the number of arrangements is 4^5=1024 (product of number of choices in each step). I used the multiplicative principle.
So you have 1024 possible 8 letter arrangements satisfying your conditions. Most of those arrangements are no doubt meaningless in English.
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Whats prime numbers

Prime numbers are those numbers (greater than 1) that cannot be divided by any number except themselves and one.
The Greek Eratosthenes created a method to find out these prime numbers, although it only worked over a limited range:
1) Write out the numbers from 1 to 100 in ten rows of 10.

hundsq.gif2) Cross off number 1, because all primes are greater than 1.
3) Number 2 is a prime, so we can keep it, but we need to cross off the multiples of 2 (i.e. even numbers).
4) Number 3 is also a prime, so again we keep it and cross off the multiples of 3.
5) The next number left is 5 (because four has been crossed off), so we keep it and cross of the multiples of this number.
6) The final number left in the first row is number 7, so cross off its multiples.
7) You have finished. All of the "surviving" numbers (coloured in white below) on your grid are prime numbers.

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Is it possible to have a remainder when dividing a number by powers and multiples of ten? Yes or No. Please give an example

Yes, it's possible because not all numbers are multiples of ten. For example if you divide 63 by 30 (which is multiple of 10) you get 2 and remainder 3 (because 63=2*30+3).
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What is the answer of this problem? I am a four digit number. My ones is twice my tens. My hundreds is five less than my ones. My thousands place is the sum of my tens and hundreds. What number am i?

There are two possible answers to the above question, 4136 and 7348.
4136
My ones is twice my tens: The 6 (the ones) is twice as big as the 3 (the tens).
My hundreds is five less than my ones: 6 (the one) - 5 = 1
My thousands place is the sum of my tens and hundreds: 3 (the tens) + 1 (the hundreds) = 4
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2002 TL WONT TACK RADIO CODE

Your vehicle's audio system will disable itself if it is disconnected from electrical power for any reason.
To make it work again, you must enter a specific five-digit code in the preset buttons. Because there are hundreds of number combinations possible from five digits, making the system work without knowing the exact code is nearly impossible.
You should have received a card that lists your audio system code number and serial number. It is best to store this card in a safe place at home. In addition, you should write the audio system's serial number in this owner's manual.

If you should happen to lose the card, you must obtain the code number from your dealer. To do this, you will need the system's serial number.

If your vehicle's battery is disconnected or goes dead, the audio system will disable itself. If this happens, you will see ''CODE'' in the frequency display the next time you
turn on the system. Use the preset buttons to enter the five-digit code.
The code is on the radio code card included in your owner's manual kit. When it is entered correctly, the radio will start playing.

If you make a mistake entering the code, do not start over; complete the five-digit sequence, then enter the correct code. You have ten tries to enter the correct code. If you are unsuccessful in ten attempts, you must then leave the system on for 1 hour before trying again.

If the code card is lost, your dealer can access your code with your radio's serial number. To access the serial number, turn the radio on. It must display ''CODE'', then turn the radio off. Push the preset 1, preset 6, and power buttons at the same time, then quickly release. The serial number will appear in two sets of four digits (information obtained from Owners Manual).

Hope helps (remember to rate this).
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UNDERSTANDING MATH PROPERTIES OF REAL NUMBERS

Hii,here is list of basic real numbers properties applying them you can solve the problems easily.


Assuming a,b,c,d are real numbers:

1)Commutative Property
a) Property of Addition: a+b = b+a
b)Property of Multiplication: ab = ba


2)Associative Property
a)Property of Addition: (a+b) + c = a + (b + c)
b)Property of Multiplication: ( ab )c = a ( bc )


3)Additive Identity:
a+0 = a where 0 is the additive identity
4)Additive Inverse:
For real number a, there exists -a such that
a+(-a) = 0
5)Multiplicative Identity:
For real number a,
1 X a = a
where 1 is the multiplicative identity
6)Multiplicative Inverse:
For real number X where a≠0, there exists 1/asuch that
a X(1/a) = 1
7)Zero Product Law:
If ab = 0, then a=0 or b=0 or both a and b = 0.

8)Distributive Properties:
a)Left distributive law
a (b + c ) = ab + ac
b)Right distributive law
(a + b) c = ac+ bc
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