Your question (?) is not clear so I will not try to guess what you really mean.
Be it as it may, the Casio FX-9860G SD can solve a polynomial equation of degree 2 or 3 with REAL coefficients. If the complex MODE is set to REAL it will find the real roots. If the complex mode is set to a+ib, it will find the real and complex roots.
Apparently it will take coefficients that are real, and will give a Ma Error if any coefficient is complex.
SOURCE: how do you find out
The following screen captures are from another Casio Graphing calculator so the menu screen may not look yours. However the instructions are identical.
Here is a sequence of screen captures to illustrate how to do it.
Turn calculator ON. Use arrow to highlight STAT and press EXE
Press F5 DIST
Then select F3 CHI
Choose Cpd or Ccd
If
you choose Cpd : you must enter the Chi value you want, and press EXE,
then the number of degrees of freedom (df) and press EXE. The Execute
command is highlighted. This allows you to perform the actions
indicated by the Thumbnails at the bottom of the screen: calculate a value or Draw the distribution.
In the example above I took Chi=1, and df=3 and pressed the CALC menu.
If I press the DRAW menu instead, the distribution is displayed.
If you want the other distribution Ccd, press Ccd instead in screen capture 4.
SOURCE: My casio fx-9860G au, wont
Just in case you did not find the Copy function I am including this screen capture from the FX-9860G SD.
The function is available at the bottom of the screen that displays the regression curve. Press Copy and select a function Y1= or Y2=. The next time you press the Draw tab the scatter plot and the regression curve will be displayed on the same screen.
SOURCE: Hello How to solve complex
The simultaneous equation solver requires the coefficients to be real. Similarly matrices must have real coefficients.
Your only alternative is to express each of A and B as a real part and imaginary part.
A= x1+iy1
B=x2+iy2.
Substitute x1+iy1 for A in the two equations.
Substitute x2+iy2 for B in the two equations. Do the algebra. Gather real parts and gather imaginary parts. Split each original equation into two equations: One equation comes from setting Real Part of left side = real part of right side (1); the other equations comes from setting the imaginary part of left side= imaginary part of right side (here 0).
Do the same procedure for the 2nd original equation.
At the end of the process you will have 4 coupled linear equations in the 4 unknowns (x1,y1,x2,y2).
Then you might want to use the calculator to solve the derived system. Once you have x1,y1,x2,y2 you reconstruct A=x1+iy1, etc.
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sory for my bad english i need solve equation in exam type:
(2+3i)x + (3+5i)y=20i
(4-3i)x - (2+2i)y= 30+10i
and me have intention to buy calculator
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