20 Most Recent Mathsoft Mathcad 12 Questions & Answers

The easiest to understand (and the longest) method is to subtract off the powers of 2. The highest power of 2 in 39.37 is 2^5=32, 39.37-32 = 7.37. The next lowest power of 2 is 16, which is greater than our number, as is 8.. 39.37 -32 = 1 (2^5) = 32 7.37 0 = 0 (2^4) = 16 7.37 0 = 0 (2^3) = 8 7.37 -4.00 =1 (2^2) = 4 3.37 - 2.00 = 1 (2^1) = 2 1.37 -1.00 = 1 (2^0) = 1 .37 0 =0 (2^(-1)) = .5 .37 -.25 = 1 (2^(-2)) = .25 .12 0 = 0 (2^(-3)) = .125 .1200 - .0625 = 1 (2^(-4)) = .0625 .05750 -.03125 = 1 (2^(-5)) = .03125 .026250 -.015625 = 1 (2^(-6)) = .015625 .010625 -.0078125 = 1 (2^(-7)) = .078125 .0028125 0 = 0 (2^(-8)) = .00390625 .0028125 -.001953125 = 1 (2^(-9)) = .001953125 .000859375 and so forth... Reading the coefficients of the powers of 2, one gets: 100111.010111101...

I believe it is still 4, even though Dostoevsky claimed that 2+2=5.

If you have the required software, it should work. Here is the reference: http://www.mathcad-store.co.uk/information/mathcad_prime_migration_guide_en-us.pdf

Sports people!

Sorry, not enough information.

234/5

At sea level ( and under atmospheric pressure) , pure water boils at 100 degree C, or 212 Fahrenheit.

A system of equations is called thus, because all equations describe a common situation. So all conditions expressed by the inequalities must be satisfied (obeyed) simultaneously.

15.30

To the nearest hundredth of a decimal point = 15.30

Go here to see how to find. Lowest common denominator

26,000

2.10

14/8*17/21 = 14 * 17 = 2*17 = 17 = 17 = 1 5/12 8 * 21 8*3 4*3 12

1/2*9/16 = 9/32

12 has factors 2*2*3 8 has factors 2*2*2 So lowest common denominator is 2*2*2*3 or 24 3/12 = 6/24 and 3/8 = 9/24

The area of a circle is pi * r^^2. For the first pond, the area is pi *14^^2. Let's say that is A For the second pond the area is pi * r^^2. Let's say that is a. But a = A/4 or, conversely 4a = A. But A = pi*14^^2 = 4a = 4(pi * r^^2) or pi*14^^2 = 4(pi*r^^2) or pi*14^^2 = 4pi*r^^2 or 14^^2 = 4*r^^2 196 = 4*r^^2 196/4 = r^^2 49=r^^2 7=r So a pond of radius 7m has an area a quarter of a circular pond of 14m.