If 2a 3b =9 and 3a 2b =16 find the value of 3a - 2b.

To solve a system of equations, there are two algebraic ways to solve them, one is by substitution, while the other is elimination.

1) 2a + 3b + 5 = 0
2) 2a + 4b + 10 = 0
-----------------------
-b -5 = 0 (subtract 2 from 1)
+b-b-5 = b
-5 = b

Substitute into 1) to solve for a.

2a + 3(-5) + 5 = 0
2a -15 + 5 = 0
2a -10 = 0
2a -10 + 10 = 10
2a = 10
---- ----
2 2

a=5
Substitute into 2) to check if we did it correctly.

2(5) + 4(-5) + 10 = 0
10 -20 + 10 = 0
0=0

Good luck.

Paul

a / b = 6 / 2 so 2a = 6b or a = 3b

a + b = 112 so 3b + b = 112 so 4b = 112 and b = 28, a = 84

what year? the cyl config changed 2002/2003 depends on vin no. I think early engines rh bank 1a 2a 3a 4a lh bank 1b 2b 3b 4b later engines rh 1357 lh 2468

-3(b-4)=-2b
Hence -3b+12 = -2b
12 = 3b-2b
b = 12

The firing order of the cylinders was 1A, 6B, 4A, 3B, 2A, 5B, 6A, 1B, 3A, 4B, 5A, 2B (where A is on the right viewed from the pilots seat- B on the left- and the rows are numbered with the front row being 1).

http://www.456fis.org/SPITFIRE_ENGINES.htm

I believe that the algebraic expression should be written as:
(a + 2b)(a^2 - 2ab - 4b^2)

which can be rewritten as:
(a + 2b)^2 * (a - 2b)


The simplified form of this expression is:
(a^3 - 2a^2b - 4ab^2 + 2a^2b - 4ab^2 - 8b^3)

which can then be further simplified as:
(a^3 - 8b^3)

1a-6b-5a-2b-3a-4b-6a-1b-2a-5b-4a-3b idle 4deg a.t.d.c. hope this helps

V6 is 1,2,3 on the right and 4,5,6 on the left....Firing order is 1,4,2,5,3,6


V8 is 1,2,3,4, on the right and 5,6,7,8, on the left.....Firing order is 1,5,4,2,6,3,7,8
Jaguar labels this as 1A,2A,3A,4A on the right and 1B,2B,3B,4B on the left and the firing order is 1A,1B,4A,2A,2B,3A,3B,4B

To communicate two devices with RS-232 ports, at hardware side you'll need 3 wires, Tx, Rx and GND, with DB 9 connectors at both sides ( A & B ) you have to connect 2A to 3B, 3A to 2B, 5A to 5B, if side A is DB-9 and B side is DB-25 the connections are 2A to 2A, 3A to 3B, 5A to 7B, at software level you'll have to setup ports as hardware handshake none, of course, working at the same parameters (speed, data bits,parity).

C = 3B = 2(A+B)
3/2 B = A+B
1/2B = A
C = 2 (1/2B + B)
C = 3B

**A = 1/2B
C = 3B
B = B

1/2B + 3B + B = 4 1/2 B
180/4.5B => B = 40

If B = 40, then A = 1/2B = 20 and C = 3B = 120.

**answer: A = 20 degrees, B = 40 degrees and C = 120 degrees.