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Posted on May 24, 2010
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How to change 20 liters per minute into volume in liters per hour

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  • Posted on May 24, 2010
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If you want to convert liters per minute into liters per hour you multiply your current rate of flow(liters per minute) by time(60 minutes) and you get 1200/lpm. This holds true for any amount of time. 15 minutes is 300 30 is 600 and so on.

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the low pressure/flow minimum is for safety and protection of unit and no adjustment to do so
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The load test measures battery performance under full current load and is the best indicator of battery condition. Load testing a battery tat is not FULLY CHARGED i.e. at 12.8 VDC can permanently damage it. Fully charge it first and then let it stand for at least an hour before the load test is done. You also need a load tester AND you should know how to perform a load test. Often the best way to load test a battery will be to take it to a battery shop and have it done there.



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12.8 VDC is 100 per cent

12.6 VDC is 75 per cent

12.3 VDC is 50 per cent

12.0 VDC is 25 per cent

11.8 VDC is 0 per cent



COLD CRANKING AMPERAGE (CCA) for a DYNA battery is 270

Battery Charging Rates/Times (Approximate)



FOR A 19 AMP HOUR DYNA AGM BATTERY



BATTERY STATE OF CHARGE is 12.8 VDC is 100 per cent Charge; Rate of Charge is N/A



BATTERY STATE OF CHARGE is 12.6 VDC is 75 per cent Charge; Rate of Charge at 3 AMP is 1.75 hours at 6 AMP is 50 minutes at 10 AMP is 30 minutes at 20 AMP is 15 minutes



BATTERY STATE OF CHARGE is 12.3 VDC is 50 per cent Charge; Rate of Charge at 3 AMP is 3.5 hours at 6 AMP is 1.75 hours at 10 AMP is 1 hour at 20 AMP is 30 minutes



BATTERY STATE OF CHARGE is 12.0 VDC is 25 per cent Charge; Rate of Charge at 3 AMP is 5 hours at 6 AMP is 2.5 hours at 10 AMP is 1.5 hours at 20 AMP is 45 minutes



BATTERY STATE OF CHARGE is 11.8 VDC is 0 per cent Charge; Rate of Charge at 3 AMP is 6 hours, 40 minutes at 6 AMP is 3 hours, 20 minutes at 10 AMP is 2 hours at 20 AMP is 1 hour



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I will assume that the percentage is per volume (20% per volume, 40 per volume.
Let x be the number of liters of the 20% solution.
What is the volume of alcohol in x-liters @20%?-----> .2x
What is the volume of alcohol in the 40 liters of solution @ 50%? Obviously 20 liters.
Amount of alcohol in the two solutions =.2x+20
After you mix the two solutions what is the resulting volume?
Resultant volume=x+40
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When mixing the two solutions, no alcohol is lost: The amount of alcohol before mixing is equal to the volume of alcohol after mixing
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I will assume that the percentage is per volume (20% per volume, 40 per volume.
Let x be the number of liters of the 20% solution.
What is the volume of alcohol in x-liters @20%?-----> .2x
What is the volume of alcohol in the 40 liters of solution @ 50%? Obviously 20 liters.
Amount of alcohol in the two solutions =.2x+20

After you mix the two solutions what is the resulting volume?
Resultant volume=x+40

Percentage of alcohol in final solution: 30% or 0.3
Quantity of alcohol in final solution =.3*(x+40)


When mixing the two solutions, no alcohol is lost: The amount of alcohol before mixing is equal to the volume of alcohol after mixing

(.2*x+.5*40) =.3*(x+40)
Solve this equation for x. (Show your work) You get x=36 Liters.
Check the result by replacing x in the equation.

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http://www.watermate.co.uk/secure/uploads/DW253%20(Small)%20new%20darlac%20pop.jpg

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Add a comment to fill out the missing details.
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Give some example of math equation?

The following are examples of expressions:
2
x
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hope that help you
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