1 + sinx = 2cos^2x - SoftMath Algebrator - Algebra Homework Solver (689076614429)

Here it is (you will have to perform the last steps).

Nevermind, i assume it's an acronym meaning with respect to x.
so the derivative of (sinx)x is: (cosx)(x) + (sinx)(1)
Simplified: xcosx + sinx

I gues this problem has no solution because both
SinX and cosX should be between -1 and +1 so it's not possible that value of SinX - cosX should be 4

1. Turn calculator ON
2. If you do not see icons press the [MENU] key.
3. Use the arrow keys to move focus on the [RUN] icon.
4. Press [EXE]
5. In RUN screen press the [OPTN].
6. After you press the down key once you highlight the line "Func Type"

Here is what you see.


The polar graph type is set by pressing F2:r=. In general r=f(theta). After the F2 key is pressed the Function type changes to r=



Now, if you press the MENU key and use arrows to focus on and select GRAPH, the function entry screen looks as in the picture below (without the 2cos(3theta))


After you enter the function (use the (X, theta, T) key below the [ALPHA] to enter the theta variable) press EXE to validate.
After drawing the r1=2cos(3theta) curve I opted to change the function to r1=2cos(5theta)


Press F6:Draw to draw the graph. Here is what you get.




Enjoy.

asinx=bsin(2x*60)=120x

Go to here and enter sin(1/2cos-14/5)=x (for) x
and you press solve and get the answer:
x =

I hope this information allows you to resolve this issue. If you need further assistance, please post back with a comment to this thread.
If I've managed to answer your question or solve a problem, please take just a moment to rate this post....thanks!

(sinX-cosX)(sinX+cosX) =(sin^2 - Cos^2X)
=Sin^2X - (1-Sin^2X)
=Sin^2X -1 + Sin^2X
=2Sin^2X -1

Zulfikar Ali
[email protected]
9899780221

whats the appropriate unit of measure for -5 1/4in - 2 2/3 in

tanx= sinx/cosx,
secx=1/cosx
1+sinx/cosx=3
1+sinx=3cosx---------->1
cosx=5-sinx------------->2

sub 2 in 1
1+sinx=3(5-sinx)
1+sinx=15-3sinx
1+4sinx=15
4sinx=14
sinx=14/4...
this is the solution..