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Posted on Feb 25, 2008
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12th science maths(derivation,vector,conic section)

Please tell me 1)Find sine of the angle between the vector a&b where. 2)which type of formulae apply.

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If a boys mass is 45.554 kg and his velocity is 20km/hour so what should be his force?

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If velocity is 20km/hr then what will be acceleration

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12th science maths(derivation,vector,conic section - noavatar_s.gif vikasfofandi
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if a boys mass is 45.554 kg and his velocity is 20km/hour so what should be his force?

Solution:- Using velocity find the acceleration...(the initial velocity might be zero) so
(velocity-initial velocity)/time*time(time square)
time u have to get by converting hors into seconds
given time is 1 hr=60 x 60 x 60 secs.

then use

Force = mass x acceleration.

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1.15x² -26x + 8

What's the question?
If you're asking for the roots, they're about 0.312 and 22.3
If you're asking for the derivative, it's 1.15x - 26
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What types of triangles

A triangle with two sides of equal length is an isosceles triangle. The side that is different from the other two is usually called the base, and the two angles at the base are equal.
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How do I use the arcsine function to transform compass degrees

Cristina,

You might be referring to something else, so let me try to knock out two birds with one stone.

The arcsine function is the inverse sine function. It will take a ratio input and produce a degree/radian output. It isn't exactly transforming anything into degrees. Instead, it is telling you the corresponding angle that goes with the ratio of opposite over hypotenuse (your input).

With that said, I am going to try to answer your question with two possible solutions.

1. To find the arcsine of a value/input (between -1 and 1) you simply have to press {[2ND]} {[SIN]} {["NUMBER"]}. For example, if I wanted the arcsine of one-half I would press {[2ND]} {[SIN]} {[.]} {[5]} {[=]}. The computer would display 30 (degrees) because the sine of thirty degrees is one-half, therefore the arcsine of one-half is 30 degrees. Inverse functions in math are often written with a faux-exponent of negative one. Inverse sine (ie arcsine) should be written in blue above the sine button on your calculator.

2. To convert a compass reading into a concrete degree measure you will NOT use arcsine. Instead, you can use the Degree-Minute-Second key which is on the TI-30X. The degree portion is naturally symbolized by the superscript o; the minute is symbolized by the single apostrophe mark, the second symbol is the quotation mark. So, to convert a compass reading of 10 degrees-30 minutes - 30 seconds you would type {[10]} {[o ' "]} {[=]} {[30]} {[o ' "]} {[ -> ]} {[=]} {[30]} {[o ' "]} {[->]} {[->]} {[=]} {[=]}. The calculator should display 10.50833333, which represents the hardcore angle measure that corresponds with 10-degrees-30minutes-30seconds. Also, it should be known that this is a much better thing to do by hand because it will deeply ingrain the basic mathematics going on. Even though we're talking about degree measures, the minutes & seconds are still at a 60 unit benchmark: meaning that there are 60 minutes in a degree and 60 seconds in a minute. Therefore, 30 minutes & 30 seconds is 30.5 seconds, which is 50.83333 percent of 1 degree. Thus, 10.5083333 degreeees. Also, you can think of it as 3600 seconds in a degree, therefore you had 1830 seconds which equated to 50.83333% of 1 degree. Thus, 10.50833333 degrees total.



Alright...I hope that helps you with either question you might have been referring to. Also, I hope you enjoyed the minor math lesson involved here. Maybe you already knew it. If that was the case then I am sorry. Either way, I own a TI-30XB Solar (among many other TI Calculators) and I highly doubt that the buttons on my calculator are starkly different from yours.

If you have more calculator or even math questions just post them on here and I'll hack away.

Arrivederci.


The Math Cheetah
www.THEMATHCHEETAH.com
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Find length of right triangle given one angle an one length

Formulas relating to right angled triangles are:
Sine = perpendicular divided by hypotenuse
Cosine = base divided by hypotenuse
Tangent = perpendicular divided by base
Sine Tangent and Cosine functions are all available in Excel
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When I'm adding component vectors, how do I get the number for 20SIN170(degrees)?

Hi,
If the default angle unit is not degree, you must set it to degree by pressing the [DRG] key. Once this is done you type
170 [SIN] [ * ]20 [ENTER]

If it feels awkward to enter the command this way you must insert parentheses to make sure calculator is evaluating the sine of 170 , not the sine of 20*170
20 [*] [( ] 170 [SIN] [)] [ENTER]
Notice that the parentheses enclose 170 [SIN]. The sine of 170 will be computed first, then the result is multiplied by 20.

Hope it helps.
Thank you for rating this solution.
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Is algedra the only tip of math that an electrician needes to now?

In general no. He/she will need some elementary vector calculus as well if he will try solve problems regarding design of various circuits powered by AC. Some elementary integral/differential calculus will be useful if he/she wants to solve more complicated problems with respect to power/energy consumption for example.Let just say Algebra is a MUST!
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What is the value of SIN15 degree and COS15 degree.....?

Hi rowanwah

The sine of an angle is only applicable is a right triangle. If you just want a number, ie, the actual value of the sine 15 degrees you can look it up on Google. Do a search for "sine and cosine functions"

If you want the mathematical description of the sine of an angle it is described as follows
In a triangle ABC, there are 3 angles angle A, angle B and angle C. There are also 3 sides, Side AB, Side AC and side BC. The sine of angle A is equal to the side opposite Angle A divided by the Hypotenuse (the longest side opposite the right angle)
The Cosine of angle A is equal to the side adjacent to Angle A divided by the hypotenuse

Hope this helps Loringh PS Please leave a rating for me Thanks
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Derivative

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Please help me to get the answer for this problem. Thank you very much!

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