Need help I have 2 Amp DLS A2..for my front system speaker Using DLS UR63s....can i use them...? can you show me? how to get dla A2 to work on 2ohm so power 2X145 watt? is sound different with 2ohm than 4ohm?

Just use both speaker outputs, no need to bridge them,

With 2 speakers wired in parallel, the impedance will be halved, so you are presenting a 1 ohm load to your amp.
Many amps can drive a 1 ohm load, but not all of them. Check the specs for your amp.

If it can't drive a 1 ohm, then you'll need to rewire them in series. 2 speakers wired in series will double the impedance, so you'll present a 4 ohm load when they're wired that way.

if the amp has a 2 outputs then i would wire the two 4ohms together, and the 2ohm by itself. and if its a 4 channel output then wire them all sepretly, if its a 1 channel output then wire the two 4ohms together and leave the 2ohm sub out

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As we agreed in chat - you are going to run your 4 channel amplifier as follows...

Front Channels of amplifier will run left and right independently.
Wire up the left speakers in parallel all + together and all - together.
This will yield a 2 Ohm load.

To the Same with the Right Side speakers - on the FRONT Right channel of the amplifier.

Now you have a 2ohm stereo load on the FRONT channels of your amplifier.

And using the BRIDGED nomenclature on the REAR channels of your amplifier - wire up your 4ohm sub mono.

Here is a crude drawing for a visual



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If your sub is 2ohm it's just left positive and right negative at the amp to the speaker. Hope this helps

Hello i_starling,

The Kicker L7's come in either 2ohm or 4ohm dual voice coil (DVC) versions.

Whatever amp they are connected to, you need to know both the impedance of your L7's and the impedance of your amp. The L7's dual voice coils can be wired to provide a total of four different loads:

2ohm coils in parallel = 1ohm load
2ohm coils in series = 4ohm load
4ohm coils in parallel = 2ohm load
4ohm coils in series = 8ohm load

Your best connection would be the one that results in a final impedance load that is supported by the amp.

Hope this helps.

it all depends on the impendance of your subs if u have duel 4ohm or duel 2ohm, 2 duel 4ohm speakers can be wired at 1ohm to the amp, and with a kx1200.1 that would be pushin 2400 peak and 1200rms
if ya have 2 duel 2ohm speaker than you can only wire them to 2ohm and would be pushing 1200 peak and 600 rms with the kx1200, so if you have the duel 4ohm i would go with the kx1200.1 and if u have the duel 2ohm i would go with the hifoncs

Hi,
This should work if channel 3 & 4 are bridged at 4 ohm.
channel 1 should be stable at 2ohm
channel 2 should be stable at 2 ohm
You can hook up the right side speakers together ( + with + and - with - ) . same thing with the left side. this will give you 2 ohm each channel. this will cause your amp to run hot (this might be tuff on the amp). It will give you right (2 speakers) and left ( 2 speakers ), no front and rear adjustement if you need to balance your sound. I think you should be better buying another amp for your sub and take your 4 channels for your 4 car speakers. this amp as a rca output that can feed the other amp ( sub amp ). it is possible to do it.

Good luck

A normal wiring setup to produce a 4-ohm load is what you usually see - each speaker is wired to one channel of the amp. This is series wiring. To get a 2-ohm load, you need to wire in parallel. Here's how:

Take sub A and wire the positive terminal to the positive terminal of channel 1 on the amp. Wire the negative terminal of sub A to the negative terminal of channel 2 on the amp. For sub B, it's the opposite - positive terminal of sub B to the positive terminal of channel 2, and the negative to the negative terminal of channel 1. That's parallel wiring, and will produce the 2-ohm loading (and subsequent increase in output) that you're seeking.

Check the A or B switches it could be they are turned off!