Want to solve quadratic equations on my casio 3650p super fx

The calculator cannot do symbolic algebra. If equation is aX^2+bX+c=0, write it in the form a(X^2+(b/a)X+(c/a))=0 and solve the quadratic equation X^2+(b/a)X+(c/a)=0. Get the approximate roots X1, and X2 (if they exist) and write your original equation in the for
a(X-X1)(X-X2)=0
Your quadratic polynomial is factored as a(X-X1)(X-X2)

Use the quadratic formula, or factor the quadratic polynomial. Once factored into a product of two first degree binomials, the roots are obtained by setting (in TURN) each binomial factor equal to zero.

You can do it the same way people did it before calculators were invented. Just use the quadratic formula: http://en.wikipedia.org/wiki/Quadratic_formula. Some sophisticated calculators have generalized equation solvers that can handle equations much more complicated than the quadratic, but the fx-82 isn't one of them.

You can do it the same way people did it before calculators were invented. Just use the quadratic formula: http://en.wikipedia.org/wiki/Quadratic_formula, and let the calculator handle the arithmetic. Some sophisticated calculators have generalized equation solvers that can handle equations much more complicated than the quadratic, but the fx-82 isn't one of them.

See if it has an equation mode, and select quadratic equations. If it has a SOLVE feature, enter equation, provide a guess and solve.

Your scientific calculator is unable to solve complex equation with complex coefficients. You should try to solve by hand directly using the quadratic formula or by factoring the polynomial in z
failing that, another way would be to set z=x+iy, substitute this for z, carry out the algebra and try to separate real and imaginary parts. But your two equations will constitute a system of two quadratic equations. I am not aware of any general method to solve coupled nonlinear equations.
Good luck.

Do you really need a calculator to solve a linear equation?
Let us see how to solve it without a calculator.
Remove the parentheses fronm the second term on the left : y-3
Use the distributive property on the last term on the right side -2y-6
Take the term -3 to the right side, changing its sign in the process (becomes +3)
Take the -2y term to the left making it +2y.
3y +2y=18+3-6 or 5y=15 and the answer is straightforward .

As to your Casio FX300ES, it cannot solve equations because it does not have an EQUATION calculation mode. The Casios FX-115ES and FX-991ES have an Equation Mode. If you use any of the two to solve an equation in one variable (linear, quadratic or other) the unknown is taken to be x by default. You would have to change the name of the variable from y to x.

You cannot solve the quadratic equation with this calculator. It does not have a solve program.

However if you wnat to create a table of values for a function (any type of function that uses the basic scientific function keys ) you use the TABLE Computational Mode.

You press MODE
You select TABLE
You enter a mathematical expression 3X^2-.33X+ 15
You generate the table of values.

Press MODE 5 to bring up the equation types. Press 3 for the quadratic. Enter the three coefficients. Press = to see the first root. If the display shows x1 then press down to see the other other root. If the display only shows x then that's a double root. Given the two roots x1 and x2, the factors of the quadratic are (x-x1) and (x-x2).

Refer to "Equation Calculations" on page E-55 of the manual and examples #094 and #095 in the appendix for examples of solving quadratic equations. If the you need the manual and/or appendix, you can download them from
http://support.casio.com/manualfile.php?rgn=1&cid=004001004

Hello,
The Casio FX-300ES does not handle symbolic algebra. So it cannot factor a general polynomial expression. The methods can be found in any book on Algebra.
However if you are interested in approximate factorization of quadratic and cubic polynomials, you can use the calculator to do that. It can solve aX^3 +bX^2+cX+d =0 and the quadratic equations.

If you want to factor a cubic polynomial P3(X) = aX^3+bX^2+cX+d , you write the corresponding cubic equation as aX^3+bX^2+cX=d =0 , then you divide all terms of the equation by a to obtain

X^3+(b/a)X^2+(c/a)X+(d/a)=0.

You use the calculator to solve (approximately) this equation.
Suppose you find the 3 roots X1,X2,and X3. Then the polynomial X^3+(b/a)X^2+(c/a)X+(d/a) can be cast in the factored form (X-X1)(X-X2)(X-X3) and the original polynomial P3(X) can be written as

P3(X) = a*(X-X1)(X-X2)(X-X3)

You can handle the quadratic polynomial the same way.

P2(X) =a*(X-X1)(X-X2) where X1, X2 are the two real roots

Hope it helps.