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erifaan davids Posted on May 20, 2019

I want to log in

Same as above

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Feena Lauren

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  • Posted on May 20, 2019
Feena Lauren
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Joined: May 10, 2019
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0helpful
1answer

How To Fix yahoo error code 1032?

Hi this issue you can resolve by below trials ;

->First things is check your internet connection
->if you do not update the app,Please update it.
->Restart or try log out & log in
->check the credentials details are correct or not.
->clear the cache memory & delete history
->if above not works try to re-install

Hope above solutions works for you.
1helpful
1answer
0helpful
1answer

How to use the log function for acidity constants? I get a syntax error

Hi,
Let Ka be the acidity constant (acid dissociation constant). The pKa is defined as the negative of the log in base 10 of the acidity constant.
pKa= - log_10(Ka) where log_10 is the logarithm in base 10.

To calculate the pKa you use the key labeled [LOG], just above [COS]. Be careful with the negative sign: For that, you use the key [(-)] just above the RCL key. Press the keys in the order specified below

pKa = [(-)] [LOG] number [ ) ] [=]

Although the right parenthesis is not required in this particular case, it is better to accustom oneself to close the parenthesis.

Hope it helps.
0helpful
1answer

I am trying to do ph problems for chemistry and I cannot figure out how to use the log button right i keep getting an error

Hello,
To use the log function press [LOG] enter the number, close the right parenthesis and press [ENTER]
[LOG] 1 [ ) ] [ENTER] gives 0.

I have a hunch your problem is not the syntax of the log function on this calculator, but the calculation of the pH from the concentration or the calculation of a concentration from the pH. So I am inserting a copy of a previous post on the question. Use it as an exemple.

Let y=10^(x) 10 to the power of x
Take the log of both tems of the equality. You get log(y)=log[10^(x)] where I used square brackets for clarity. But from the general properties of logarithms

log(b^(a)) = a*log(b)

Applied to our expression above log(10^x)=x*log10
But since we are using log as log in base 10, log_10(10)=1 so log(y)=x
We thus have two equivalent relations

y=10^x <----> x=log(y) The double arrow stands for equivalence.

If y is the log of x, then x is the antilog of y

Your question: With log_10 standing for logarithm in base 10
pH=-log_10(c) where c= concentration. Then log_10(c)=-pH
The equivalence above translates as
log_10(c)=-pH is equivalent to c=10^(-pH)

The concentartion corresponding to a pH of 7.41 is
c=10^(-7.41)=3.89x10^(-8)

Hope it helps
1helpful
1answer

How do i use the inv log for calculations on my sharp el-531wh

Hello,

Let y=10^(x) 10 to the power of x
Take the log of both tems of the equality. You get
log(y)=log[10^(x)] where I used square brackets for clarity. But from the general properties of logarithms

log(b^(a)) = a*log(b)
Applied to our expression above
log(10^x)=x*log10
But since we are using log as log in base 10, log_10(10)=1
so
log(y)=x
We thus have two equivalent relations
y=10^x <----> x=log(y) The double arrow stands for equivalence.

If y is the log of x, then x is the antilog of y

Your question: With log_10 standing for logarith in base 10
pH=-log_10(c) c= concentration
Then log_10(c)=-pH the equivalence above translates as
log_10(c)=-pH is equivalent to c=10^(-pH)

The concentartion corresponding to a pH of 7.41 is
c=10^(-7.41)=3.89x10^(-8)

You enter it as follows
10[^]7.41[(-)][ENTER/=]

Hope it helps

6helpful
1answer

How to find anti-log

Hello,
If you know the theory skip this and go to Application
Let y=10^(x) 10 to the power of x
Take the log of both tems of the equality. You get
log(y)=log[10^(x)] where I used square brackets for clarity. But from the general properties of logarithms

log(b^(a)) = a*log(b)
Applied to our expression above
log(10^x)=x*log10
But since we are using log as log in base 10, log_10(10)=1
so
log(y)=x
We thus have two equivalent relations
y=10^x <----> x=log(y) The double arrow stands for equivalence.

If y is the log of x, then x is the antilog of y

Application: What is the antilog of 3.76?
antilog of 3.76 =10^(3.76) = 5754.399373
Take the log in base 10 of this number and you recover 3.76

You enter it as follows
10[^]3.76[ENTER/=] gives 5754.399373
And log(5754.399373)= 3.76

Hope it helps
0helpful
1answer

How to convert log

Hello, The first remark is this. The ratio log(0.8)/log(2) is by definition binary log of 0.8 ( meanibg log in base 2 of 0.8) The second remark is good news for you.: When in MathIO, [SHIFT][MODE][1:MathI0], your calculator can compute directly the log in any base of any number. To use the functionality, you press the key below [ON]. It is a log symbols with a small solid square, and and erect empty rectangle.
When you press the key the screen shos a template. In the smaller and lowered square goes the base (here 2). When you enter the base, press the right arrow to move cursor to the rectangle inside the parentheses and type in 0.8. Use the right arrow to move the cursor out of the parentheses.
Practice: try that. the result should be -0.321928095. Good. Now use the replay button to move cursor to the command line outside the right parenthesis. I am going to give you the other key stokes. Let log(2,0.8) be my representation for log in base2 of 0.8. Then you enter the rest of the calculation as
log(2, 0.8) [*] [ ( ] [(-)] 0.321 [ ) ] [*] 2500 [=]
Here [*] is the multiplication sign [(-)] is the negation (change sign), just above the [RCL] key.
[ ( ] is the left parenthesis and [ ) ] its matching right parenthesis. Both of them enclose the number -0.321. It underlined them for clarity.
The result should be 259.0716344
If you do not like what I did above, you can always do things the old way. You use the log key just above the [COS] key. In that case -0.3219*[LOG] (0.80)/[LOG] 2 * 2500. Do not to supply the ) for both log. The calculator inserts the left ones by default.
Hope it helps.
0helpful
1answer

Locked mailbox. Contact admin. I've used feature 983 but the passwords 1020000,120000,10020000 won't work. I am prompted for 'log'. If I just bypass 'log' by pressing OK, it takes me to password and it...

Try this: "Feature" 983, Enter 120000 or the system coordinator password, press "ok", press "mbx", press "chng", then enter the mail box number, press "reset", then release. The mail box password should default to "oooo"
0helpful
1answer

Activity log

Step 1 Open a web browser and type the IP address of the wireless router in the address bar (default is 192.168.0.1). Press Enter. Step 2 The default username is admin (all lower case) and the default password is blank (nothing). Click OK. Step 3 Click the Status tab and then click Log to the left. This page displays the activity log for your wireless router. The buttons located above the log can be used to perform the below actions: First Page - View the first page of the log. Last Page - View the last page of the log. Previous - View the previous page of the log. Next - View the next page of the log. Clear - Clear (delete) the entire log. Log Settings - Configure advanced options for the activity log.
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