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Posted on Aug 04, 2009

A(24)=40,000e((ln2/26)24) The population of a southern city follows the exponential law. If the popluation doubled in size over 26 months and the current population is 40,000, what will the population be 2 years from now? So far I have got to k= ln2/26 A(24)=40,000e((ln2/26)24) I am lost from here. I can't seem to get the next step right.

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  • Posted on Aug 12, 2009
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Your best bet in any kind of exponential equation is to set up the general form of the equation and then solve for the constants with the numbers they gave you. With P being population, t being time, you know it is going to look like P=Ae^(b*t) and you are given 2 P's for 2 t's.

So for the first set :

Eq 1 P(26)=40,000=Ae^(b*26)

and the second being a time t=0 P was half the current value:

Eq 2 P(0)=20,000=Ae^(b*0)
20,000=A*1 so A=20,000

now b from Eq 1

40,000=20,000e^(b*26)






  • Anonymous Aug 12, 2009

    er... i hit enter too many times.. but anyways you already found that constant, hope it helped.


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