Your best bet in any kind of exponential equation is to set up the general form of the equation and then solve for the constants with the numbers they gave you. With P being population, t being time, you know it is going to look like P=Ae^(b*t) and you are given 2 P's for 2 t's.
So for the first set :
Eq 1 P(26)=40,000=Ae^(b*26)
and the second being a time t=0 P was half the current value:
Eq 2 P(0)=20,000=Ae^(b*0)
20,000=A*1 so A=20,000
now b from Eq 1
40,000=20,000e^(b*26)
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