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What is the ohms law? - Car Audio & Video

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Ohm's law states that the current through a conductor between two points is directly proportional to the voltage across the two points. Introducing the constant of proportionality, the resistance, one arrives at the usual mathematical equation that describes this relationship: I= V/R. Much more you can find at the https://fnblegal.com where I is the current through the conductor in units of amperes, V is the voltage measured across the conductor in units of volts, and R is the resistance of the conductor in units of ohms. More specifically, Ohm's law states that the R in this relation is constant, independent of the current. Ohm's law is an empirical relation which accurately describes the conductivity of the vast majority of electrically conductive materials over many orders of magnitude of current. However some materials do not obey Ohm's law, these are called non-ohmic.

Posted on Jun 14, 2019

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Ohm's law
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noun PHYSICS
unpunctuated: Ohms law

  1. a law stating that electric current is proportional to voltage and inversely proportional to resistance.
    or try this link.
What is the ohms law Google Search

Posted on Aug 17, 2018

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Posted on Aug 17, 2018

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1 Answer

Can I bridge my 1200watt 2channel sony xplod amplifier?


How many ohms at two channels, remenber ohms law, amp should be stable at lower ohm RMS wattage..whenn you say 1200 watts its that full wattage, now you got a RMS wattage..What is it?

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Wire 3 12 " p2 2 ohm to 1001 watts hifonics brutus


best i can tell, the amp is stable @ 1 ohm, but 6 colis x 2o ohms is 12 ohms, and 2 ohms divided by 6 drivers is 1/3 of an ohm. you will have to study ohmms law, and parallel versus serial wiring resistance results to get as close to 1 ohm, without going under it. i honestly thing that 1.66 ohm is the closest you will get

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Circuit calcultions


Use Kerchovs Law alongside Ohms Law.

Feb 10, 2014 | Computers & Internet

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What is my current rate


Which current are you referring to ??......



If you think of an electrical device as a piece of plumbing, voltage is the amount of water that you send down into the pipe, resistance is the pipe's relative width or narrowness, and current is the speed with which the water flows.
Power measures the water's relative difficulty or ease making its way through the pipe.
You relate all these values to one another using a common set of physics equations known as Ohm's law.
If you need to calculate electricity's current flow, you'll need to have at least two of the three values -- voltage, resistance or power -- listed above.

Calculate current flow using voltage and resistance.
According to Ohm's law, you can express electricity's current in amps as a ratio of its voltage in volts to the resistance of the device it's flowing through in ohms -- I = E/R, respectively.
For example, if you want to know the current flow of 220 V of electricity as it flows through a laptop computer with 80 ohms of resistance, you would simply plug these values into the equation as follows: I = 220/80 = 2.75 amps.
Calculate current flow using power and resistance.
Ohm's law also states that electrical current, "I," is equal to the square root of the power dissipated as it travels through the device divided by that device's resistance.
If a light bulb dissipates 80 watts of power and has a resistance of 55 ohms, you can calculate the electricity's current as follows: I = sqrt(80/55) = sqrt(1.4545) = 1.20 amps.

Calculate current flow using power and voltage.
If you have a space heater which dissipates 420 watts of power when it takes in 120 V of electricity, Ohm's law states you can calculate this electricity's current using the equation "I = P/E." For this example, compute current like so: I =420/120 = 3.5 amps.

http://www.the12volt.com/ohm/ohmslaw.asp

Aug 13, 2013 | Computers & Internet

1 Answer

I have two 2 ohm subwoofers and one 4 ohm subwoofers and i want to wire all them together as a 2 ohm load. How do I do that?


Ohms law in series and parallel circuits: look it up.

If you parallel attach them all you'll come in too low.

From admittedly faulty memory: 1/x + 1/y.... = 1/total

A 2-ohm load is unusually low. Not many amps will survive high levels at 2 ohms.

IF YOU MUST:

I'd run the two 2-ohm units in series (total = 4 ohms), then run that set in parallel with the 4 ohm sub. Total = 2 ohms.

You give no indication of their similarities .Good luck matching up the volumes. And keep a fire extinguisher handy.

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1 Answer

Probe wire is damaged


it will have to be replaced. any repair could change resistance if checking ohms and change any readings it will take. look up ohms law online and it will explain the relationship between voltage,amperage, and ohms

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1 Answer

Im looking for the best electrical calculator for ohms law and kirchoffs law


Hello,
To solve Ohm's law you need no sophisticated calculator. If you know two quantities, you readily calculate the third. Application of Kirchhoff's (two h) laws to linear circuits, gives you a linear system of equations. If a calculator can solve linear systems, or handles matrices, the limitations would pertain to the maximum dimension of the matrices.
I just tried the TI83 to define a 45x45 square matrix and a 55x45 matrix. The maximum number of rows or columns is 99. But it will depend on memory.
If you have the TI84PLUS Silver Edition it should be fine. You can upgrade to a TI 89 Platinum, which can handle symbolic calculations (with undefined coefficients a, b, c).
Hope it helps.

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The line fuse blows on power up. Input impeadance to the power transformre is 3 ohms. Is this correct? seems low.


Ohms law I=V/R which is 240vac divided by 3 ohm = 80 amps. Dead short which is either the windings, or the mains filter capacitor which has gone short circuit which is more the likely culprit. This is on the output side of the fuse. If you have a meter switched to ohms and measure across this capacitor you will read zero ohms (dead short) which confirms the capacitor. Disconnect one side and if the short goes, then it's the cap, if not, it's the transformer.

Sep 12, 2009 | Cambridge Soundworks BassCube 8 Speaker

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Given a current of 10amps and a resistance of 500ohms what is the voltage plz could u help me on this


Ohms law can be applied here . When applying Ohms circuits are taken as perfect with no additional deviations to values introduced by connections or temperature, so although not exactly correct it is a very good guide. Almost all electical calcs can be done with Ohms law and its variations.

so
V(volts) = I(current) x R (resistance)

I x R =5000
so V =5000

Answer is 5000 Volts

Apr 28, 2008 | Audio Players & Recorders

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