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Florence Nelson Posted on Aug 03, 2017
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What is the perimeter and area of a rectangle with a length of 11 yds and awidthof 12 yds

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Terry Weaver

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  • Master 412 Answers
  • Posted on Aug 03, 2017
Terry Weaver
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Seriously?

Perimeter 11+11+12+12= 46 yd.

Area 11*12= 132 sq. yd.

Bill Boyd

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  • The Master 53,816 Answers
  • Posted on Aug 03, 2017
Bill Boyd
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Perimeter is 2X( L + B)
so that is 2 X (11+12)= 2 X 23 = 46 yards
area is LX B =11X12=132 square yards
grade 3 maths really

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5 Related Answers

Anonymous

  • 3 Answers
  • Posted on Mar 08, 2009

SOURCE: is rx-v659 compatible with new ipod dock YDS-11

Both docks will work with your receiver.

Dank

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Anonymous

  • 292 Answers
  • Posted on Sep 19, 2009

SOURCE: area of rectangle having length 1 fit and width 3

Hi amita_mediai

Do this:
1*3*20
Explanation
Multiply the length and the width. This gives the area in sq ft. Multiply this with 20. This will be the cost in rs.
Good luck
luciana44

Anonymous

  • 128 Answers
  • Posted on Jun 05, 2010

SOURCE: finding pair of linear equations

23 inches Width

Marek Podmaka

  • 127 Answers
  • Posted on Jan 28, 2011

SOURCE: I have a Yamaha RX-V465

Yes, it is compatible.
http://usa.yamaha.com/products/audio-visual/accessories/yds-12_black__u/?mode=model

It has 2 modes of operation. For RX-V465 you need to select mode B. In this mode it is compatible with YDS-11, which is supported for RX-V465. But iPhone is not officially supported in this mode. But I have found on Yamaha website FAQ, where they claim that iPhone switched to Airplane mode worked well.

http://faq.yamaha.com/us/en/article/audio-visual/accessories/yds-12_black__u/4742/4061

johnwmaustin

John Austin

  • 222 Answers
  • Posted on Sep 28, 2012

SOURCE: Write a Java application that finds a. Area and perimeter of rectangle. b. Area and circumference of a circle.Display explanatory text with the value

Did you find a solution for this ?

You haven't received any help because the request looks a lot like a homework assignment and a lot of people are unwilling to do that.

I have some suggestions:

1) You should make sure that you have a working copy of Java. Start at the Java Tutorial: http://docs.oracle.com/javase/tutorial/java/TOC.html

If you do not have a working Java on your machine, follow the link at the top right of that screen to 'Download JDK'. That is the set of programming tools you need to use to compile and run programs.

The Installation Instructions will tell you everything you wish to know. I suggest that you use: http://notepad-plus-plus.org/ to type in programs.

Good luck. Post more on the problem page for more help.

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Related Questions:

0helpful
1answer

Find the perimeter and area of a rectangle with a length of 11 yards and a width of 12 yards

the perimeter of any square sided object is 2 times the height added to 2 times the width: (2h)+(2w). The actual answer for your sizes is 46 yards given by 2 times 11 plus 2 times 12. Hope this helps.
0helpful
1answer

The length, l, of a rectangle is 5/2 its width, w. The length, l, of the rectangle is 10 inches. What is the perimeter of the rectangle? What Iis the area of the rectangle, in sauare inches?

We are given the following data:

length = 5/2 * width
length = 10 inWe know through the transitive

property of equality that the following must be true:

5/2 * width = 10 in

We then solve this equation algebraically for width:

width = (10 in) * 2/5
width = 4 in

The perimeter of the rectangle is given by substituting our known values of length and width into the following general equation:

Perimeter = 2 * length + 2 * width
Perimeter = 2(10 in) + 2(4 in) = 28 in

In a similar fashion, we substitute these known values into the general equation for the area of the rectangle to solve for the same:

Area = length * width
Area = (10 in)(4 in)=40 in^2
0helpful
1answer

A rectangle is 5 feet long and 6 feet wide. what is the perimeter of the rectangle?

Hi Jacqueline:
A rectangle has four sides, the lengths of the opposite sides are equal, and the corners are right angles.
The perimeter is the distance around the outside edge, so it would be twice the length plus twice the width.
2 times 5 = 10 feet
2 times 6 = 12 feet
10 plus 12 = 22 feet

What is important is to understand the question.
If you need help with the course, get back to me.
Cheerfuls!
0helpful
1answer

What is the greatest perimeter that a 48 meter squared rectangle could have?

Infinite.

A one meter by 48 meter rectangle has an area of 48 square meters and a perimeter of 98 meters. A one centimeter by 4800 meter rectangle has the same area and a perimeter of 9600.02 meters. A one millimeter by 48,000 meter rectangle has the same area and a perimeter of 96,000.002 meters. A rectangle one micron by 48,000,000 meters has an area of 48 square meters and a perimeter of 96,000,000.000002 meters. Keep making the rectangle skinnier and skinnier without changing the area, and the perimeter keeps getting longer and longer.
0helpful
2answers
0helpful
1answer

Perimeter of a 1 x 3 rectangle

Rectangle has two pairs of equal sides.
L=length=3 units
w=width =1 unit
Perimeter = sum of the measures of all sides.
2 sides with measure L: sum of lengths=2*L
2 sides with measure w: sum of widths=2*w
Perimeter = 2L+2w=2(L+w)=2(1+3)=8 units.
0helpful
2answers

How do you solve a rectangle is eight inches longer than its width. find the dimensions of the rectangle if the perimeter is 60 cm

The rectangle is 11cm by 19cm.

The perimeter is 60, so the width and length must add to 30. The length is 8 more than the width, or width+width+8=30. Solve that for width, then you can calculate the length based on the width.

If this is homework, be sure to show your work.
0helpful
1answer

Please show all of the information and answers to: The plane was purchased new in 2006; therefore, x =0 represents the year 2006. X - Axis (horizontal) = years starting from 0 = 2006 and increasing b

Translate the English into Mathematics.
W=L-5 (in inches)
P=2(L+W)=2(L+L-5)=2(2L-5)
Use distirbutive property of multiplication with respect to addition to open up the parentheses (brackets)
P=4L-10.
Set P= 50 (inches), to get 4L-10=50
Solve for L: Do it'!
Find W= L (the one you just found) -5 =

Now, with W the value you just calculated
the new length is L'=-4+3W
and the new perimeter is P'=2(L'+W)

Now your turn to do some work.
0helpful
1answer

Area and perimeter

Area= width * length
Perimeter= 2 * width + 2* length

Are you looking for an Excel function?
There are no Area or Perimeter functions I am aware of in Excel.
Not finding what you are looking for?

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