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When I use the fatmax to measure a distance, it gives the answer in inches. Is there anyway that I can reset/program the fatmax to give me the measurements in feet
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The formula for 45 degree bends is offset" x 1.414 equals the travel distance in inches. Example: to calculate the offset of a line 6 1/4", in other words move the line over. Turm 1/4 into decimal form (1 divided by 4=.25). Calculate: (6.25 x 1.414= 8.8375). To convert the decimal form of .8375 to a fraction multiply it by 16 (16/16=1") example: .8375 x 16=13.4 , 13 is the numerator, 16 is the denominator which gives you a fraction of 13/16". That gives you your travel distance center to center of a 6 1/4" offset= 8 13/16" travel distance. For accuracy in your measurement, you must subtract the fitting allowance (how much space the fittings take up in the measurement) from your overall travel distance. It sounds like a lot of steps, but using this formula gives you dead on accuracy in pipe fitting. If you know your travel distance and wish to find the offset, multiply x .707. Hope this helps.
This is, of course, a trick question. The simple answer is 12, because the circumference of the park is 420m and 12 x 420m is 5040m. However, we are not told how close to the edge the runner is able to run, nor whether he (or she) rounds off the corners. If, for example, the park is bounded by a fence, the runner may have to run 1m inside the fence and will almost certainly not run completely in to each corner. Adjusting for these factors could reduce the distance run per lap to 410m or less, in which case an additional lap will be necessary. In fact, if the actual distance run is less than 416.67m per lap, then 13 laps must be run.
Press the red button - (distance) you will see a red dot on the wall you are measuring - then you will hear a beep - release the button and read the display - the measurement should be displayed and accurate within a quarter inch.
You could do a bit of research as i can't remember the math's from my college days, but, it is possible to calculate the distance something travels by using its rate of descent against the time it takes to reach the ground, for instance, if gravity is measured at 9.81N/m per sec squared, then an object must speed up at the same rate from standstil every time unless the earths gravitational pull changed. If you then timed how long it takes to hit the ground you could do a simple calculation offsetting the rate of descent against time which would then give your distance. The calculation is - distance = speed x time, but you would need to factor in the the rate of change in the speed of the object from standstill to finish which is the bit i can't remember.
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