IF LENGTH and WIDTH are given How to find Hight

We are given the following data:

length = 5/2 * width
length = 10 inWe know through the transitive

property of equality that the following must be true:

5/2 * width = 10 in

We then solve this equation algebraically for width:

width = (10 in) * 2/5
width = 4 in

The perimeter of the rectangle is given by substituting our known values of length and width into the following general equation:

Perimeter = 2 * length + 2 * width
Perimeter = 2(10 in) + 2(4 in) = 28 in

In a similar fashion, we substitute these known values into the general equation for the area of the rectangle to solve for the same:

Area = length * width
Area = (10 in)(4 in)=40 in^2

There is no relation between square anything to cubic anything.
If you want to calculate how many cubic feet 312 sq tiles are, you need to tell how this the tiles are.
Cubic is length x width x hight.
square is length x width.
All in the same dimension so even 1/4 of an inch, should be added in feet. with 0,00xx I don't want to calculate in these old measures anymore.

of what

Say length is x.
Width is x-24.
Perimeter is length plus width plus length plus width = 228.
x + (x-24) + x + (x-24) = 228
4x-48 = 228
4x=276
x=69
length = 69
width = 69-24= 45

check: 45 + 69 + 45 + 69 = 228

What pits are you talking about?
Do you mean dents, for an accident report?
If so, then just take digital photos and send printo outs in with the report.

u need 1 hp unit

Here is the Solution:

1. Convert 15 ft into yards. 1 yard = 3 feet
=> 15 ft = 5 yd

2. Find the area of the given room. The cost for given room is given, and cost for carpeting 1 sq. yd is given. So,
800/20 = 40 {i.e. 40 sq. yd (area of the given room)}

3. Now, Length * Width = Area
=> x * 5 = 40 [Taking Length = x yd]
=> x = 40/5
=> x = 8 yd
=> x = 8 * 3 ft
=> x = 24 ft

So, Length of the given room is 24 ft (8yd).

I hope this solved your problem (in time).

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