Area 40 ft long 4ft wide 5 inches deep how many sq yards needed

Allow me to rephrase your question... You want to know the volume of water necessary to saturate a 4ft by 4ft area to a depth of 4 in?


Start with the square of the area and convert units to inches.
4'x4' = 16 ft. sq.
1 ft. sq. = 144 in. sq.
Thus 16 x 144 = 2304 in. sq.


Now sum the cubic inches to depth of 4"
2304 x 4 = 9216 in. cu. total necessary water volume.


Since US residents typically measure water volume by gals. convert inches cubed into gallons. 231 in cu / gal (US)
9216 / 231 = 39.8 gal.

So about 40 gallons of water would be needed to saturate a 4ftx4ft area to a depth of 4 inches.

you have to many numbers there
If you are saying 12'x15'x what deep 3 inches or 3' ?
12'x15'=180 sq ft x3' = 540 cubic feet or 20 cubic yards
x3inches= 40 cubic feet

No, there are 9 feet in a square yard.

Do you mean how many cubic yards it would require to fill a volume occupied by an area of 30 ft by 40 ft by 4 ins deep? If this is what you mean then it would require 11.1 cubic yards. Hope this helps.Sorry I can't help with the cost.

AC is approx. 145 lbs per cubic ft.
there are 27 cubic ft in 1 cubic yard
60 tons x 2000 = 120000 divided by 145 = 827.58 cubic ft divided by 27 = 30.65 cubic yards

square yards would depend on thickness of AC.
you can take thickness x sq ft to get cubic ft

in concrete 1 cubic yard =
4 inch thickness = 81 sq ft or 9 sq yrds
6 inch thickness = 54 sq ft or 6 sq yards

Cubic foot is a unit of volume. Square foot is a unit of area. There is no conversion.

Let's say you have 2000 cubic feet of mulch. That can cover a 2000 square foot yard one foot deep. It can also cover a one square foot flowerbed 2000 feet deep.

Hello, to solve your question about what number to use to calibrate your broadcast spreader, please use the step-by-step instructions below:

1. If you don't already know the square footage of your lawn, please walk off or measure, multiplying the length by width. For example, my lawn is 100 ft wide by 100 ft long; this equals 10,000 sq. ft.
2. Use this figure (30,000 sq ft) to determine how much fertilizer, insecticide, fungicide,apply etc., to purchase and apply.
3. To calibrate the spreader for applying your product at the correct rate, first weigh and hold out an amount of product to cover a pre-determined test area; for example, enough for a 200 sq ft space.
4. Because most lawn fertilizers are packaged to cover areas in 1000 sq ft increments, it's easy to figure how many 1,000 sq ft applications you need for your lawn.
5. Set your spreader to 3 and measure 1/5 of the recommended application on your product, to cover a 200 sq ft area.
6. Use your spreader to cover this 200 sq ft area.
7. If there is product remaining in the hopper after walking this 200 sq ft area, increase the setting number and move to another test area, repeat steps 5 and 6.
8. If there wasn't enough product to cover the test area, back the number down, move to another test area, and repeat steps 5 and 6, until you finish with product and lawn test area at the same time.
9. Remember to never leave product in your hopper because many chemicals are corrosive and can destroy the moving parts, making the spreader inoperable.

I hope this helps!

The answer is 40.123456789

To convert square feet to square inches x 144 (i.e 12 x 12)

1200 x 144 = 374400

Multiply by 5 (depth) to give cubic inches

374400 x 5 = 1872000

To convert cubic inches to cubic feet divide by 46656 (36 x 36 x 36)

1872000 / 46656 = 40.123456789

Hope this helps,

Matt

24 x 5 x 1.33 = 160 cubic feet
160 cf / 27 = 5.93 (or around 6 cubic yards)

Here is the Solution:

1. Convert 15 ft into yards. 1 yard = 3 feet
=> 15 ft = 5 yd

2. Find the area of the given room. The cost for given room is given, and cost for carpeting 1 sq. yd is given. So,
800/20 = 40 {i.e. 40 sq. yd (area of the given room)}

3. Now, Length * Width = Area
=> x * 5 = 40 [Taking Length = x yd]
=> x = 40/5
=> x = 8 yd
=> x = 8 * 3 ft
=> x = 24 ft

So, Length of the given room is 24 ft (8yd).

I hope this solved your problem (in time).