What does P1 P2 P3 and P4 mean? - Computers & Internet

While in heating or cooling press the temp hold button behind the door. Hold will be displayed rather than p1, p2 p3 or p4.

If you need further help, reach me via phone at https://www.6ya.com/expert/thomas_092728000e6acb79

HI,
Error 2 means P0 P1 P2 P4 P5 ( P0 ....Min. ,Speed P1 ....Max, Speed P2 ....Mid.Speed, P4 ....Min.Slope, P5 ....Max.Slope )have a wrong parameter values. You have to go the engineering mode and set the parameter. Here i have added a link which will guide you to the service manual of Jet 7000. read the section 4 (console maintenance mode guide) and re-calibrate the treadmill parameters P0 P1 P2 P4 P5 .page no(4.3).

http://www.cross-ir.com/Downloads/JET7000-6000-1.PDF
WWW.electro-medical.blogspot.com

It is a possibility. I understand your frustration with treadmills. The P1 - P4 are programmed events. I am sure there is a way to make it just run after setting it to 3mph. Send me more information on the treadmill including name and model number...year if you know it.

P3 code refers to the probe near the airgap at the back. It is monitoring the rinse temp. P2 is the booser probe, and P1 is the wash tank. The control board will store error codes, so once changed, you can access the memory and clear it.

process allocation Max
A B C D A B C D
p1 0 0 1 2 0 0 1 2
p2 2 0 0 0 2 7 5 0
p3 0 0 3 4 6 6 5 6
p4 2 3 5 4 4 3 5 6
p5 0 3 3 2 0 6 5 6

total recourses in a system (r1,r2,r3,r4)=(6,7,12,12)
(i) Calculate available resource martrix & need matrix for state of
system
(ii) determine saftey if Iexits for the system applying banker's
algorithm.
(iii) p3 request for(0,1,0,0) . does this request lead to a deadlock?

After I stitch out the p1, I have to go back and load the p2 design and continue stitching after I adjust the hoop to the p2 setting. Then I do the same thing with the p3. It is a pain to go back and forth, but it works!

I m providing you this from my college notes

Banker's Algorithm


* multiple instances of resource types IMPLIES cannot use resource-allocation graph

* banks do not allocate cash unless they can satisfy customer needs when a new process enters the system

* declare in advance maximum need for each resource type

* cannot exceed the total resources of that type

* later, processes make actual request for some resources

* if the the allocation leaves system in safe state grant the resources

* otherwise, suspend process until other processes release enough resources



Banker: Data Structures define MAXN 10 /* maximum number of processes */
#define MAXM 10 /* maximum number of resource types */
int Available[MAXM]; /* Available[j] = current # of unused resource j */
int Max[MAXN][MAXM]; /* Max[i][j] = max demand of i for resource j */
int Allocation[MAXN][MAXM]; /* Allocation[i][j] = i's current allocation of j*/
int Need[MAXN][MAXM]; /* Need[i][j] = i's potential for more j */
/* Need[i][j] = Max[i][j] - Allocation[i][j] */

Notation:

X <= Y iff X[i] <= Y[i] for all i

(0,3,2,1) is less than (1,7,3,2)

(1,7,3,2) is NOT less than (0,8,2,1)

Each row of Allocation and Need are vectors: Allocation_i and Need_i



Banker: Example

Initially:

Available
A B C
10 5 7

Later Snapshot:

Max - Allocation = Need Available
A B C A B C A B C A B C
P0 7 5 3 0 1 0 7 4 3 3 3 2
P1 3 2 2 2 0 0 1 2 2
P2 9 0 2 3 0 2 6 0 0
P3 2 2 2 2 1 1 0 1 1
P4 4 3 3 0 0 2 4 3 1



Banker: Safety Algorithm

* consider some sequence of processes

* if the first process has Need less than Available

* it can run until done

* then release all of its allocated resources

* allocation is increased for next process

* if the second process has Need less than Available

* ...

* then all of the processes will be able to run eventually

* IMPLIES system is in a safe state



Banker: Safety Algorithm

STEP 1: initialize
Work := Available;
for i = 1,2,...,n
Finish[i] = false
STEP 2: find i such that both
a. Finish[i] is false
b. Need_i <= Work
if no such i, goto STEP 4
STEP 3:
Work := Work + Allocation_i
Finish[i] = true
goto STEP 2
STEP 4:
if Finish[i] = true for all i, system is in safe state



Banker: Safety Example

Using the previous example, P1,P3,P4,P2,P0 satisfies criteria.

Max - Allocation = Need <= Work Available
A B C A B C A B C A B C
P1 3 2 2 2 0 0 1 2 2 3 3 2 3 3 2
P3 2 2 2 2 1 1 0 1 1 5 3 2
P4 4 3 3 0 0 2 4 3 1 7 4 3
P2 9 0 2 3 0 2 6 0 0 7 4 5
P0 7 5 3 0 1 0 7 4 3 10 4 7
10 5 7<<< initial system



Banker: Resource-Request Algorithm

STEP 0: P_i makes Request_i for resources, say (1,0,2)
STEP 1: if Request_i <= Need_i
goto STEP 2
else ERROR
STEP 2: if Request_i <= Available
goto STEP 3
else suspend P_i
STEP 3: pretend to allocate requested resources
Available := Available - Request_i
Allocation_i := Allocation_i + Request_i;
Need_i := Need_i - Request_i
STEP 4: if pretend state is SAFE
then do a real allocation and P_i proceeds
else
restore the original state and suspend P_i



Banker: Resource-Request Algorithm [129]

Say P1 requests (1,0,2)

Compare to Need_1: (1,0,2) <= (1,2,2)

Compare to Available: (1,0,2) <= (3 3 2)

Pretend to allocate resources:

Max - Allocation = Need Available
A B C A B C A B C A B C
P0 7 5 3 0 1 0 7 4 3 2 3 0<<<
P1 3 2 2 3 0 2<<< 0 2 0<<<
P2 9 0 2 3 0 2 6 0 0
P3 2 2 2 2 1 1 0 1 1
P4 4 3 3 0 0 2 4 3 1

Is this safe? Yes: P1, P3, P4, P0, P2

Can P4 get (3,3,0)? No, (3,3,0) > (2,3,0) Available

Can P0 get (0,2,0)? (0,2,0) < (2,3,0) Available

Pretend: Available goes to (2,1,0)

Thanks And Regards

Slot 1 - P2 (DS CARD slot)
SLot 2 P1 (GBA CARD SLOT)
P3,P4 are the flex clip for up and down lcd screen
and others par number, i always check on www.logictoyz.com, some times,they have image there

for all os ? you must use java language! this is the code:

//<applet code="calmayank"height=300 width=300></applet>
import java.awt.*;
import javax.swing.*;
import java.awt.event.*;

public class calmayank extends JApplet
implements ActionListener
{
JTextField t1;

JButton b1,b2,b3,b4,b5,b6,b7,b8,b9,b10,
b11,b12,b13,b14,b15,b16,b17,b18,b19,b20;

GridLayout gl;
JPanel p1,p2,p3;

public void init()
{
gl=new GridLayout(5,4);
p1=new JPanel();
p2=new JPanel();
p3=new JPanel();
p1.setLayout(gl);
t1=new JTextField(17);
b1=new JButton("1");
b2=new JButton("2");
b3=new JButton("3");
b4=new JButton("4");
b5=new JButton("5");
b6=new JButton("6");
b7=new JButton("7");
b8=new JButton("8");
b9=new JButton("9");
b10=new JButton("0");
b11=new JButton("+");
b12=new JButton("-");
b13=new JButton("*");
b14=new JButton("/");
b15=new JButton("@");
b16=new JButton("$");
b17=new JButton("%");
b18=new JButton(".");
b19=new JButton("?");
b20=new JButton("=");


p2.add(t1);

p1.add(b1);
p1.add(b2);
p1.add(b3);
p1.add(b4);
p1.add(b5);
p1.add(b6);
p1.add(b7);
p1.add(b8);
p1.add(b9);
p1.add(b10);
p1.add(b11);
p1.add(b12);
p1.add(b13);
p1.add(b14);
p1.add(b15);
p1.add(b16);
p1.add(b17);
p1.add(b18);
p1.add(b19);
p1.add(b20);
p3.add(p2);
p3.add(p1);
getContentPane().add(p3);

b1.addActionListener(this);
b2.addActionListener(this);
b3.addActionListener(this);
b4.addActionListener(this);
b5.addActionListener(this);
b6.addActionListener(this);
b7.addActionListener(this);
b8.addActionListener(this);
b9.addActionListener(this);
}
public void actionPerformed(ActionEvent e)
{
if(e.getSource()==b1)
{
t1.setText("1");
}
else if(e.getSource()==b2)
{
t1.setText("2");
}
else if(e.getSource()==b3)
{
t1.setText("3");
}
else if(e.getSource()==b4)
{
t1.setText("4");
}
else if(e.getSource()==b5)
{
t1.setText("5");
}
else if(e.getSource()==b6)
{
t1.setText("6");
}
else if(e.getSource()==b7)
{
t1.setText("7");
}
else if(e.getSource()==b8)
{
t1.setText("8");
}
else if(e.getSource()==b9)
{
t1.setText("9");
}
}
}

easy all 4 pin dont matter 4 pin to all hard drives and cd roms ok big 20 pin or 24 to mobo smaller 4 pins floppies ok dont mater that its says p1 p2 3p that dont meen nothing ok 4 pin plugs main ones uuse on cd roms hard drives ok fans sumtimes