The time (T) required to drive a fixed distance varies inversely as the speed (r). If it takes 5 hours at 80km/h to drive a fixed distance,how long would it take to drive the fixed distance at 50km/h?

The speed limit is 65mph I believe

You can go to Map Quest for that info

How long it takes to drive any distance depends on your average speed. Whatever is your average speed, divide that into the distance you have to travel. For instance, if your speed is 100 kilometers per hour and you need to go 400 kilometers, it will take you (400 km/100 kmph=) four hours. Always be sure to use the same units of measurement, English or metric, in your arithmetic.

About 54.4 milliroentgens per hour.

If this is homework, be sure to show your work.

The cosine of 52 degrees is about .6157 . The inverse cosine of .6157 is 52 degrees.

52 degrees is a measure of an angle. .6157 is a distance. The cosine of an angle results in a distance, while the inverse cosine of a distance results in an angle. There is no such thing as the inverse cosine of an angle, just as there is no such thing as the cosine of a distance. It's like asking "How heavy is one hour?"

If you're asking how to calculate a cosine or inverse cosine on your calculator, please specify the make and model of the calculator.

I have the same problem for two weeks, three times I ordered dragged checked my fuel pump replaced sensor passed over gas pump and the fuel filter fuel filter checked syringes All right already and high costs
Car turns off the light in the car there's watches on 'CHECK' 'but it seems gust mal engine fuel pressure monitoring -p1181
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Assume X is the intensity of the radition at 0 meters.
Then 62.5 milliroentgens/hr = 1/(3^2) * X
Solve for X. X = 9 * 62.5 milliroentgens = 562.5 milliroentgens/hr
Now solve for the radiation at 2.5 meters.
R = 1/(2.5^2) * 562.5 milliroentgens = 562.5/6.25 = 90 milliroentgens/hr

I hope this helps you out.

The stopping distance is proportional to square of speed.

that is 90ft proportional to 40^2 mph.

We can write as 90 = X * 40^2. ( X is a constant of proportionality) .

Which implies X = 90 / 1600 = .05625.

Assume S be the distance at which car stops when the speed is 90 mph.

S = X * 90^2. ( since X does not vary as same car is used)

=> S =.05625 * 8100 = 455.625 ft.

Thank you.

Let X be the time taken when train is moving in its normal speed.

Y be the normal speed of the train.

Speed = distance/time

that is X = 400 / Y

or Y = 400 / X --------- (1)

When speed is decreased by 5 km/hr time increases by 4 hour

that is X + 4 = 400 / Y -5

= X + 4 = 400 X / 400 - 5X ( substitute Y = 400 /X we get this equation)


on solving we get 5X^2 + 20x - 1600 = 0

we get two solutions X = 16 and -20

-20 is neglected (time cannot be negative)

substitute X in equation (1)

Y = 400 / 16 = 25 km/hr

So normal speed of train is 25 km/hr.