2x2-3x+5=0 solving the quadratic equation
Here you are :
2X2-3x+5=0
=> 4-3x+5=0; (2X2=4)
=> -3x+9=0; (4+5=9)
=> 9 = 3x; (-3x moved to the right-hand side and it became 3x)
=> 9/3=x; (3 moved to the right hand side, so it becomes 1/3, i.e 1/3X9= 9/3)
i.e. x=9/3
=> x=3
Hence x equals to 3.
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