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Find two numbers such that the sum of the first and three times the second is 5 and the sum of the second and 2 times the first is 8

1 Answer

Bapco

Expert 290 Answers
Posted on Jun 19, 2014

Bapco

Expert

Joined: Jan 23, 2011

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Let the two numbers be X and Y:
X + 3Y = 5
2X + Y = 8

Rewrite the second equation to Y = 8 - 2X and substitute in first equation:
X + 3(8-2X) = 5
X + 24 - 6X = 5
-5X + 24 = 5
-5X = 5 - 24
-5X = -19
X = 19/5 = 3.8
Y = 8 - 2(3.8) = 8 - 7.6 = 0.4

Check: 3.8 + 3(0.4) = 3.8 + 1.2 = 5
2(3.8) + .4 = 7.6 + 0.4 = 8

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