Draw the developnent of lateral surface of pentagonal pyramid of base side 30mm and axis height 60mm

Do your own homework.? How will you learn anything if you ask other people to do it for you.? How will you know if people are lying about the answers, because they know, that you DON'T know.?

The volume is one third the product of the area of the base times the height or (1/3)B*h

Assuming the base of the pyramid is square ... of length B and the distance from the center of the base of the pyramid to the top of the pyramid is H

Surface area is: 2 x H x B
plus B-square (if you include the base of the pyramid)

A pyramid has 5 sides including the base. If the base is a rectangle L long and W wide, its area is L*W.

The other sides are triangles. If the height of the pyramid is H, the triangles that are L wide at the base will have a height of the square root of half of W squared plus H squared, or SQRT((.5*W)^2+H^2) and the two that are W wide at the base will have a height of SQRT((.5*L)^2+H^2). The area of a triangle is .5*height*base, so the total surface two triangles with the same height and base is 2*.5*height*base = height*base.

So, the total surface area of a pyramid L long by W wide by H tall would be:
L*W (the area of the base)
+ L*SQRT((.5*W)^2+H^2) (the area of the 2 triangles with base L)
+ W*SQRT((.5*L)^2+H^2) (the area of the 2 triangles with base W)

Hope this is helpful!

Here is to get you started. To increase the size of the image do a CTRL Plus (+) in your browser.
You need to calculate the slant height of the pyramid for the formula of the lateral area. You should find a value of (1/2)*SQRT(203) or about 7.1239 cm



You need to calculate the altitude (height) of the pyramid from the apex (summit) to the center of the base triangle (center of inscribed circle, barycenter, orthocenter). The hypotenuse of such triangle is the slant height. One leg is the altitude (to be found), the measure of the second leg is (1/3) the altitude of the equilateral triangle that forms the base. You should find (1/3) m MH= (1/3)* (11/2)*SQRT(3)


1. Calculate the area of the base (use a formula for the equilateral triangle or the general formula for a triangle: you have its height MH ).
2. Lateral area = 3 times the area of triangle Triangle ECD (in yellow above).
3. Total area = area of base + lateral area.
4. Volume= (1/3)(Area of base)* (height of pyramid)
If you can see the details on the screen capture below, fine, Press CTRL + in your browser to increase the size.

I assume you mean a square base.

2.0833 litres.

If this is homework, be sure to show your work.

2.0833 litres.

If this is homework, be sure to show your work.

A pyramid is made of triangles, and the number of triangles for a particular pyramid base. For a square base pyramid - 4 triangles; pentagonal base - 5 triangles

Pencils broke!

The first Egyptian pyramid was 204 feet or 62 meters high, built at the direction on Pharoah Djoser in around 2630 B.C. The tallest was the Great Pyramid at Giza, standing at an impressive 481 feet or 147 meters. The smallest was the Pyramid of Pepi II, which stood at a paltry 172 feet or 52 meters. Just based on Egyptian pyramids, the average height is about 316.5 feet or 96.375 meters. Considering the technology of the day, the pyramid builders were quite impressive to say the least. Hope this helped and best wishes.