Math equations a television set and a mini component together cost Php 17 500. if the television set costs Php 1500 more than the component, how much does each cost?

A great tutorial: https://www.khanacademy.org/math/cc-eighth-grade-math/cc-8th-linear-equations-functions/8th-slope-intercept-form/v/linear-equations-in-slope-intercept-form

Math homework, but an English lesson involved: Proper spelling is "equation."

Offhand I see possibly that we need to set up to solve 5690/6600= X/100 and cross-multiply, then solve for X

Do again for 950/6600=Y/100 and cross multiply. Solve for Y.

At least we get to put something together that replaces the original equation with X%+Y%=100%

Now, I am leading up to Y% is the percentage change, but I need to bone-up on that point myself. Perhaps I have triggered the thought juices.

You will never learn any mathematics if you do not solve math problems. I am here to do your homework. I will however help you set the problem up.
1. Define variables (unknowns).
2. Let t be the price of the tennis shoes
3. Let r be the price of running shoes.
Translate the text into mathematical expressions
A pair of running shoes costs 5$ more than a pair of tennis shoes
5 $ more ---> ... +5
Cost of a pair of running shoes (r) = cost of a pair of tennis shoes (t) +5
So the first statement can be expressed as r=t+5

The total cost of both ------> Sum of the costs r+t
The total cost of both is 115 $ ------> r+t=115

Now you have a system of two linear equations in two unknowns
( r=t+5
)
(r+t=115
There are a few methods to solve the system (comparison, substitution, or combination/addition/elimination). I gave the 3 possible names for the third methods.
Choose a method and solve the system to find t and r.
Note: Although all three methods, if carried out correctly, will give you the same solution (t,r), one of them should be preferred. It is worthwhile to recognize immediately which method should be favored depending on the system you are dealing with.

if ur using pcl driver try with ps driver other wise make it pdf and try to print

Let p be the cost of a pear, and a the cost of an apple.
First statement
6p+3a=3.90 OR 2p+a=1.3 (I simplified by 3)
Second statement
2p+5a=3.30

Solve the system.
I suggest you multiply the first equation by (-1) then add side to side. You will be able to find a. Plug the value of a in one of the original equation and solve for p

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16
$60 - $12 = 48
48/3 =
= 16 rides @ £3 each

The Frank I know would negotiate a block booking with discount and mess up and maths

For this type of problem, a equals the constant cost of operation (monthly rent..etc) and b equals the cost to manufacture the items.

first equation: 320 = a + b(10)
second equation: 520 = a +b(20)

320 = a + 10b
520 = a + 20b subtract equation 2 from equation 1

-200 = -10b divide by -10

20 = b plug b into one of the equations

320 = a +(20)(10) multiply

320 = a +200 subtract 200

120 = a

Let me know if i need to explain further.

Hi romanam
If spoon is "s" and fork is "f"
you get 2 equations like:
4s + 3f = 15 equation 1
4s + 1f = 13 equation 2
Equation (1) - equation (2) gives :
2f = 2 which means
1f = 1 (dividing both sides by 2)
! fork costs $1
5 forks cost $5
If you are happy with the answer, please give a rating
luciana44