Write a program c that declares an array of 100 elements to hold these values. Read the values in from the file and store them in successive elements of the array. Keep track of how many numbers are read in as it is an undefined amount of numbers less than 100. Once you have the numbers in an array calculate the average value of these numbers and display the answer. Then use the brute force approach to find the maximum value of the numbers and report the value and what position in the array that value occurs at.

the nice thing about pseudocode is that there's many ways to do it
E.g 1;
String str = new Array["einstein',"newton"];
E.g 2;
myStringArray = new Array{'einstein','newton'}

BOTH of the above are correct, because they are pseudocode

You need to assign a default value to your variable, otherwise it's just declared and not initialized.
Example (in C#):
int numericValue; Here the variable numericValue has been declared as an integer
int numericValue = 11; and here the variable has been declared and initialized as an integer with the value 11.

You could do this by creating two arrays as such:
int firstArray[5]; int secondArray[5]
and then the sum variable:
int sum = 0;
then you could do a for loop to find the sum of the second array:

suppose you have declared a array of 5 ( ie 0-4 ) and you are entering the value for 6 or we can say more than 5 then you will receive this error and also you have not declared the catch block or exception block for this exception to handle the error .

Hi.

I suggest creating an Array of Cards (cardOne,cardTwo,etc. to five)

If you can enter them in one at a time, after declaring the array, assign the values to the array.

cin < cardOne; (Psuedo code by the way, hope you don't mind)

Afterwards, you'll have an array with 5 cards.

Declare what full houses, flushes, etc would require.
Use an if statement (If you don't mind lots of code) to compare the entered Array against possible hands.

I didn't necessarily give you any specific C++ code. However, if you Google C++ user input, you should find plenty of commands that may help you.

Good Luck

(And not sure about Linear search to be honest, you can use a Linear search, but if you did it the way I explained, you just have to compare hand to a series of conditionals.)

NEED A NEW KEY THE ONE ON THE BOX WONT WORK

Need help doing your homework?

Here's a solution, written in BASIC:

10 PRINT, "Hello World"
20 EXIT

http://www.cplusplus.com/doc/tutorial/

you

An array is a series of elements of the same type placed in contiguous memory locations that can be individually referenced by adding an index to a unique identifier
Initializing arrays. When declaring a regular array of local scope (within a function, for example), if we do not specify otherwise, its elements will not be initialized to any value by default, so their content will be undetermined until we store some value in them. The elements of global and static arrays, on the other hand, are automatically initialized with their default values, which for all fundamental types this means they are filled with zeros
include <iostream>
using namespace std;

int billy [] = {16, 2, 77, 40, 12071};
int n, result=0;

int main ()
{
for ( n=0 ; n<5 ; n++ )
{
result += billy[n];
}
cout << result;
return 0;
}
multidimensional array pseudo-multidimensional array #define WIDTH 5 #define HEIGHT 3 int jimmy [HEIGHT][WIDTH]; int n,m; int main () { for (n=0;n<HEIGHT;n++) for (m=0;m<WIDTH;m++) { jimmy[n][m]=(n+1)*(m+1); } return 0; } #define WIDTH 5 #define HEIGHT 3 int jimmy [HEIGHT * WIDTH]; int n,m; int main () { for (n=0;n<HEIGHT;n++) for (m=0;m<WIDTH;m++) { jimmy[n*WIDTH+m]=(n+1)*(m+1); } return 0; }
and now for trignometry
#include<iostream>
#include<cmath>
using namespace std;

int main()
{
int factorial(int);
int n = 3, i = 1;
double x, x2, b, PI, r;
char choice;
//r = x * (PI / 180)

cout<<"Please enter an angle value => ";
cin>>x;
cout<<"Is the angle value in Degree or Radian?"<<endl;
cout<<"Type D if its in degree "<<endl;
cout<<"Type R if its in radian "<<endl;
cin>>choice;


if((choice = 'R')||(choice = 'r'))
do{
i++; n = 3; x2 = 0; b = x2;
{
if(i == 1)
x2 = x - (pow(x,n) /factorial(n));
n = n + 2;
};
else
{
x2 = (x2 + ((pow(x,n)) /(factorial(n))) - (pow(x,n+2)) / (factorial(n+2)));
n = n + 4;
}


}while(abs(b - x2) > 0.000001);
else
//convert it to r

r = x * PI /180;

//cout<<"error occured/n";
cout<<"sin(x) = "<<x2<<endl;

return 0;
}