help sec^4X- sec^2X = 1/cot^4X + 1/cot^2X sec^4X- sec^2X = 1/cot^4X + 1/cot^2X RHS 1/cot^4X + 1/cot^2X =1/(Cos^4X/Sin^4X) + 1/(Cos^2X/Sin^2X) =Sin^4X/Cos^4X + Sin^2X/Cos^2X =Sin^4X/Cos^4X + Cos^2X.Sin
Foil Method 2(3x-4)(4x+5) Hello, You have the method: apply it. 2 *(3x-4)(4x+5) =(6x-8)(4x+5) Now apply the FOIL method F: 6x*4x=24x^2 O: 6x*5=30x I; -8*4x=-32x L: -8*5=-40 so the result is 24x^2 + ...
4x-(2x-3)=0 4x-(2x-3)=0 =>4x-2x+3=0 ; (after the bracket's oepned and multiplied by - [minus]) =>2x+3=0 ; taken x as common and 4-2=2 i.e. x(4-2) = 2x =>2x=-3 ; +3's moved on the right-hand ...
4x+8y=20 -4x+2y=-30 4x+8y=20 || /4 x+2y=5 x=5-2y -4x+2y=-30 || /2 -2x+y=-15 -2(5-2y)+y=-15 -10+4y+y=-15 5y=-5 y=-1 x=5-2y || y=-1 x=5-2(-1) x=5+2 x=7
what is the inverse of 3x/4x-1 If your question is the inverse of 3x / (4x - 1) then (4x - 1) / 3x If you meant (3x / 4x) - 1 then - 4
. x^3 - 4x^2 - 12x Hii,you can use the following solution x^3 - 4x^2-12x=0 x(x^2-4x-12)=0 replacing -4x from -6x+2x x(x^2-6x+2x-12)=0 Now Factoring x(x(x-6) +2(x-6))=0 x(x-6)(x+2)=0 Solution is x=0, x
2(3-x)+3(x-1)=4x help solve x equals 1 First multiply the numbers outside the parentheses by what is inside the parentheses, which results in: 6 - 2x + 3x - 3 = 4x then combine what you can: 6 - 3 = 3
...and the focus) a = 2 (2 units above the vertex) (x-h)^2 = 4a (y-k) (x-2)^2 = 4(2) (y-0) x^2 - 4x + 4 = 8 (y) x^2 - 4x + 4 = 8y x^2 - 4x - 8y + 4 = 0 **Answer: "(x-2)^2 = 8 (y)" or in expanded ...
-20=-4x-6x THIS IS FOR INFINITE ALGEBRA 1 -20=-4x-6x try to collect the like terms:-20=-10x divide both sides the coefficient of X which -10 X=-20/-10 X=2 -20=-4x-6x => -20 = -10x => 10x = 20 ...
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