help sec^4X- sec^2X = 1/cot^4X + 1/cot^2X sec^4X- sec^2X = 1/cot^4X + 1/cot^2X RHS 1/cot^4X + 1/cot^2X =1/(Cos^4X/Sin^4X) + 1/(Cos^2X/Sin^2X) =Sin^4X/Cos^4X + Sin^2X/Cos^2X =Sin^4X/Cos^4X + Cos^2X.Sin
Differentiate each of the following w.r.t.x; 29.sin2xsinx Use the rule for differentiating products of functions: ()' signifies derivative (29*sin(2X)*sin(X))'= (29)'*sin(2X)*sin(X) +29* ...
4x-(2x-3)=0 4x-(2x-3)=0 =>4x-2x+3=0 ; (after the bracket's oepned and multiplied by - [minus]) =>2x+3=0 ; taken x as common and 4-2=2 i.e. x(4-2) = 2x =>2x=-3 ; +3's moved on the right-hand ...
(sin-cos)(sin+cos) help!! (sinX-cosX)(sinX+cosX) =(sin^2 - Cos^2X) =Sin^2X - (1-Sin^2X) =Sin^2X -1 + Sin^2X =2Sin^2X -1 Zulfikar Ali [email protected] 9899780221
what is rational expression of (22x +11) (10x2 +5x) I assume the 10x2 means 10 squared. (I will show it as 10x**2) (22x+11)(10x**2+5x) factors ...
...-3Y=9-4 -3Y=5 -Y=5/3 Y=-1.67 A. 3X+(-1.67)=2 3X-1.67=2 3X=2+1.67 3X=3.67 X=3.67/3 X=1.22 (3x-2y)2 = 2x=4 3x+y=2;2x-y sol'n: 3x+y=2 y=2x-3 3x+2x-3=2 5x\5=2+3\5 x=1 3(1)+y=2 3+y=2 y=2-3 y=-1 ...
...is 7. In 3 years Edwin will be 17. Edwin will be 10. (3*10 - 13 = 17) Let x=Ruel's age now, and 2x=Edwin's age now. 2x+3=3(x+3)-13 2x+3=3x+9-13 2x+3=3x-4 2x+7=3x 7=x If you are going to post
...1 I tried to it on my own and my friends also tried to help me Now is the equation supposed to be y=2x+1? If so, The graph of y = 2x+1 is a straight line When x increases, y increases twice as fast, ...
how to identify the x and y intercepts for a line y=2x-3 ? & 2x+y-6=0? Hi Melissa:2x + (2x-3) - 6 = 04x - 9 = 0x = 9/4 Then y = 3/2Hope this helps; also keep in mind that your feedback is ...
(2x - 5) - (x - 2) i need the solution for this There is nothing to solve because you have no equation (no = sign) nor an inequality ( no <,or >.) All you can do is use distributivity to open up
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